Focus
Trending Questions
Q. If (2, 0) is vertex and y−axis is the directrix of a parabola. Then its focus will be
- (0, 0)
- (2, 0)
- (4, 0)
- (−2, 0)
Q. The extremities of latus rectum of a parabola are (1, 1) and (1, −1). Then the equation(s) of the parabola is/are
- y2=2x−1
- y2=1−2x
- y2=3−2x
- y2=2x−3
Q.
The coordinates of the focus of the parabola y2−x−2y+2=0 are
(54, 1)
(14, 0)
(1, 1)
none of these
Q. The focus of the parabola y2=4y−4x is
- (1, 2)
- (2, 0)
- (2, 1)
- (0, 2)
Q.
The focus of the parabola y=2x2+x is
(−14, 0)
(−14, 18)
(0, 0)
(12, 14)
Q. The length of latus rectum of parabola 4y2+3x+3y+1=0 is
- 43
- 7
- 12
- 34
Q. If the focus of the parabola x2−ky+3=0 is (0, 2), then the value(s) of k is/are
- 4
- 6
- 3
- 2
Q.
The latus rectum of parabola y2=5x+4y+1 is
Q. The equation of reflection of y2=x about y−axis is
- y2−x=0
- x2+y=0
- x+y2=0
- x2−y=0
Q. The locus of the centre of a circle passing through a point and touching a line is
- a parabola
- a hyperbola
- an ellipse
- a straight line
Q. Co-ordinate of the focus of the parabola x2−4x−8y−4=0 are
Q. The parabola y2=px passes through the point of intersection of lines x3+y2=1 and x2+y3=1 its focus is
- (310, 0)
- (35, 0)
- (37, 0)
- (67, 0)
Q. From any point P(h, k), four normal can be drawn to the rectangular hyperbola xy=c2 such that product of the abscissae of the feet of the normal = product of the ordinates of the feet of the normal is equal to
Q. The end points of the latus rectum of a parabola having vertex at origin are (4, 8) and (4, −8) then the equation of the parabola is
- y2=4x
- y2=8x
- y2=16x
- x2=8y
Q.
The focus of the parabola x2−2x=2y is
Q. Let P(x) and Q(x) be two polynomials. Suppose that f(x)=P(x3)+xQ(x3) is divisible by x2+x+1, then
- P(x) is divisible by (x−1), but Q(x) is not divisible by (x−1)
- Q(x) is divisible by (x−1), but P(x) is not divisible by (x−1)
- Both P(x) and Q(x) are divisible by (x−1)
- f(x) is divisible by (x3−1)
Q. The coordinates of focus of parabola 9y2−9x−12y−57=0 is
- (−23536, −23)
- (−23536, 23)
- (23536, 23)
- (23536, −23)
Q. If (2, 0) is vertex and y−axis is the directrix of a parabola. Then its focus will be
- (0, 0)
- (2, 0)
- (4, 0)
- (−2, 0)
Q. The focus of the parabola y2=4y−4x is
- (0, 2)
- (1, 2)
- (2, 0)
- (2, 1)
Q.
The latus rectum of parabola y2=5x+4y+1 is
54
10
5
52
Q. value of x satisfying the equality |x2+8x+7|=|x2+4x+4|+|4x+3| for x∈R are
- (34, ∞)∪{−2}
- [−34, ∞)∪{−2}
- (−2, ∞)
- (−43, ∞)
Q. The coordinates of the focus of the parabola described parametrically by x=5t2+2 and y=10t+4 are
- (7, 4)
- (3, 4)
- (3, −4)
- (−7, 4)
Q. Let P be the point (1, 0) and Q be a point on the curve y2=8x. Then the locus of the mid-point of PQ is
- y2+4x+2=0
- y2−4x+2=0
- x2−4y+2=0
- x2+4y+2=0
Q. A ray of light travels along a line y=4 and strikes the surface of a curves y2=4(x+y), then equation of the line along which reflected ray travels is
- 2x+y=4
- x+y=4
- x=0
- x=2
Q. Equation x2−2x−2y+5=0 represents
- a parabola with vertex (1, 2)
- a parabola with directrix y=25
- a parabola with vertex (2, 1)
- a parabola with directrix y=32
Q. Find the vertex, axis, latus rectum, and focus of the parabolas x2+2y=8x−7.
Q. Consider a circle with center lying on the focus of the parabola y2=2px such that it touches the directrix of the parabola, then a point of intersection of the circle and the parabola is
- (−p2, −p)
- (p2, p)
- (p2, −p)
- (−p2, p)
Q. Find the equation of the circle passing through the points (1, 1), (−1, −2) and whose centre lies on the line x+2y=1
Q. The parabola y2=px passes through the point of intersection of lines x3+y2=1 and x2+y3=1 its focus is
- (310, 0)
- (35, 0)
- (37, 0)
- (67, 0)
Q. Let P be the point (1, 0) and Q a point on the curve y2=8x. The locus of mid point of PQ is-
- y2−4x+2=0
- y2+4x+2=0
- x2+4y+2=0
- x2−4y+2=0