Geometrical Representation of Conjugate of a Complex Number
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Q. Let s, t, r be non-zero complex numbers and L be the set of solutions z=x+iy (x, y∈R, i=√−1) of the equation sz+t¯z+r=0, where ¯z=x−iy. Then, which of the following statement(s) is (are) TRUE?
- If L has exactly one element, then |s|≠|t|
- If |s|=|t|, then L has infinitely many elements
- The number of elements in L∩{z:|z−1+i|=5} is atmost 2
- If L has more than one element, then L has infinitely many elements
Q. Let C be the set of all complex numbers. Let S1={z∈C:|z−3−2i|2=8},
S2={z∈C:Re(z)≥5} and
S3={z∈C:|z−¯z|≥8}.
Then the number of elements in S1∩S2∩S3 is equal to
S2={z∈C:Re(z)≥5} and
S3={z∈C:|z−¯z|≥8}.
Then the number of elements in S1∩S2∩S3 is equal to
- 0
- 1
- 2
- Infinite
Q.
Find the values of other five trigonometric functions if , x lies in third quadrant.