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Let R be the relation in the set N given by R = {(a, b): a = b - 2, b > 6}. Choose the correct answer.
(A)(2, 4)∈R(B)(3, 8)∈R(C)(6, 8)∈R(D)(8, 7)∈R
Solution set of is given by
None of these
Then which among the following options is/are correct for g(x) in [0, 2]
- g(x) is continuous for all x
- g(x) is differentiable for all x
- g(x) is discontinuous at x=1
- g(x) is not differentiable at x=1
What should be the relation between range and codomain of a function, for a function to be an onto function -
Range > Co domain
Range = Co domain
None of the above
Range < Co domain
Jamey has quarters, some dimes, and some pennies. If the ratio of quarters to dimes is and the ratio of pennies to dimes is , then how many pennies does Jamey have?
then the number of preimages of 3 is
- {(1, a), (3, b), (2, a), (2, b)}
- None of the above
- {(1, a), (2, b)}
- {(1, b), (2, a), (3, a)}
Then the correct options is/are
- Image of 2 under f is 4
- Image of 5 under f is 10
- Preimage of 4 under f is 8
- Preimage of 6 under f is 3
then the image of 1 is
If A = {1, 2, 3, 4, 5, 6, 7, 8, 9} Relation R from A to A by R = {(x, y):y = x + 3}. Find Domain, Co domain and Range of R.
Domain = {2, 3, 4, 5, 6}, Co-domain = {1, 2, 3, 4, 5, 6, 7, 8, 9}, Range = {4, 5, 6, 7, 8, 9}
Domain = {1, 2, 3, 4, 5, 6}, Co-domain = {1, 2, 3, 4, 5, 6, 7, 8, 9}, Range = {4, 5, 6, 7, 8, 9}
Domain = {1, 2, 3, 4, 5, 6, 7, 8, 9}, Co-domain = {1, 2, 3, 4, 5, 6, 7, 8, 9}, Range = {1, 2, 3, 4, 5, 6, 7, 8, 9}
Domain = {1, 2, 3, 4, 5}, Co-domain = {6, 7, 8, 9}, Range = {6, 7, 8, 9}
(vi) 12×4= ––––––– and 12ax2×4ax= –––––––
Number of ways of selecting four letters from proportion
then the image of 1 is
Then the correct options is/are
- Image of 2 under f is 4
- Image of 5 under f is 10
- Preimage of 4 under f is 8
- Preimage of 6 under f is 3
If f(x)=⎧⎪
⎪⎨⎪
⎪⎩x2, when x<0x, when 0≤x<11x, when x>1
Find: (i) f(12)
(ii) f(−2)
(iii) f(1)
(iv) f(√3)
(v) f(√−3)
- R1={(x, a):a=x+2, x∈X, a∈Y}
- R2={(1, 1), (2, 1), (3, 3), (4, 3), (5, 5)}
- R3={(1, 1), (1, 3), (3, 5), (3, 7), (5, 7)}
- R4={(1, 3), (2, 5), (4, 7), (5, 9), (3, 1)}
- {1, 2, 3, …, 10}
- {2, 4, 6, 8}
- {2, 4, 6, 8, 10}
- {1, 2, 3, 4}
- a=0
- a>0
- a<0
- a≤0
- Range
- Domain
- none of these
- mapping
- R1={(x, y)|y=2+x, x∈X, y∈Y}
- R2={(1, 1), (2, 1), (3, 3), (4, 3), (5, 5)}
- R4={(1, 3), (2, 5), (2, 4), (7, 9)}
- R3={(1, 1), (1, 3), (3, 5), (3, 7), (5, 7)}
Which of the following is/are correct?
Domain of R = set of first components of all the ordered pairs which belong to R
Domain of R = set of second components of all the ordered pairs which belong to R
Range of R = set of second components of all the ordered pairs which belong to R
Range of R = set of first components of all the ordered pairs which belong to R
range f = f
range f = R
range f = constant
range f = {constant}
- z, z
- z+, z
- z, z−
- None of these