Integration of Piecewise Continuous Functions
Trending Questions
How do you integrate .
- −4
- −5
- −√2−√3−1
- −√2−√3+1
is continuous at x=0, then 1a+1b+4k is equal to:
- 5
- 4
- −4
- −5
What is the formula of ?
- (12, 1]
- (0, 12]
- (1, 2)
- (2, 3)
- f(x)=1ln|x|
- f(x)=cos(|sinx|x)
- f(x)=x sin(πx)
- f(x)=11+2 cotx
Assertion: The sum of two vectors can be zero. Reason: The vector cancels each other when they are equal and opposite.
both Assertion and Reason are true and the Reason is the correct explanation of the Assertion.
both Assertion and Reason are true but Reason is not the correct explanation of the Assertion.
Assertion is true but Reason is false.
Assertion and Reason both are false.
Assertion is false but Reason is true
Differential coefficient of w.r.t. is
none of these
PROPERTY 1 if limh→0f(h)−f(0)√|h| exists and is finite, and
PROPERTY 2 if limh→0f(h)−f(0)h2exists and is finite.
Then which of the following options is/are correct?
- f(x)=|x| has PROPERTY 1
- f(x)=x23 has PROPERTY 1
- f(x)=x|x| has PROPERTY 2
- f(x)=sinx has PROPERTY 2
Integrate the following functions.
∫19x2+6x+5dx.
- 27
- 54
- −54
- 0
Evaluate :
- −π
- 0
- −π2
- π2
Evaluate :
The value of I=∫30([x]+[x+13]+[x+23])dx, where [⋅] denotes the greatest integer function, is equal to
10
11
12
14
- g(x) is even
- g(n)=0, n∈N
- g(2n)=0, n∈N
- g(x) is non-periodic
The second-order derivative of with respect to at is
- 5
- 8
- -2
- 3
If , then the value of is
- 0
- -1
- 1
- 2
- 1I2+I4, 1I3+I5, 1I4+I6 are in G.P.
- 1I2+I4, 1I3+I5, 1I4+I6 are in A.P.
- I2+I4, I3+I5, I4+I6 are in A.P.
- I2+I4, (I3+I5)2, I4+I6 are in G.P.