L'Hospital Rule to Remove Indeterminate Form
Trending Questions
Q.
Explain rule of differentiation.
Q.
limx→∞(13+132+133+....+13n)
Q.
limn→∞(1n2+2n2+3n2+....+n−1n2)
Q. If L=limx→0(tanxx)1/x2, then the value of 1lnL is
Q. If limx→0ax−(e4x−1)ax(e4x−1) exists and is equal to b, then the value of a–2b is
Q.
Evaluate :
Q.
If , then
None of these
Q.
If where , then is equal to:
Q. limy → 0 √1+√1+y4 − √2y4
- does not exist
- exists and equals 12√2
- exists and equals 14√2
- exists and equals 12√2 (√2+1)
Q.
How do you simplify the expression ?
Q. limx→0x+2sinx√x2+2sinx+1−√sin2x−x+1=
- 1
- 2
- 3
- 6
Q.
The number of values of in the interval satisfying the equation is
Q. Statement 1: f(x)=sinx+[x] is discontinuous at x=0, where [.] denotes the greatest integer function.
Statement 2: If g(x) is continuous and h(x) is discontinuous at x=a, then g(x)+h(x) will necessarily be discontinuous at x=a.
Statement 2: If g(x) is continuous and h(x) is discontinuous at x=a, then g(x)+h(x) will necessarily be discontinuous at x=a.
- Both the statements are true and statement 2 is the correct explanation of statement1.
- Both the statements are true and statement 2 is not the correct explanation of statement 1.
- statement 1 is true andstatement 2 is false
- statement 1 is false and statement 2 is true
Q. If limx→1x2−ax+bx−1=5, then a+b is equal to :
- 5
- 1
- −7
- −4
Q.
The value of at , where is given by , is
Q. Given that for each a∈(0, 1),
limh→0+1−h∫ht−a(1−t)a−1 dt
exists. Let this limit be g(a). In addition, it is given that the function g(a) is differentiable on (0, 1).
The value of g′(12) is
limh→0+1−h∫ht−a(1−t)a−1 dt
exists. Let this limit be g(a). In addition, it is given that the function g(a) is differentiable on (0, 1).
The value of g′(12) is
- π2
- π
- −π2
- 0
Q. Evaluate the limit:
limx→0sin3x+7x4x+sin2x
limx→0sin3x+7x4x+sin2x
Q.
What is in terms of and ?
Q.
The differential coefficient of the given function is
Q.
limn→∞13+23+33+....+n3n4
Q. If limx→01x8[1−cosx22−cosx24+cosx22cosx24]=2−k, then the value of k is
Q. Let f:R→R be a continuously differentiable function such that f(2)=6 and f′(2)=148.
If f(x)∫64t3 dt=(x−2)g(x), then limx→2 g(x) is equal to
If f(x)∫64t3 dt=(x−2)g(x), then limx→2 g(x) is equal to
- 12
- 18
- 24
- 36
Q. Let f:R→R be a differentiable function satisfying f′(3)+f′(2)=0. Then limx→0(1+f(3+x)−f(3)1+f(2−x)−f(2))1/x is equal to :
- e
- e−1
- e2
- 1
Q. limx→0ex2−cosxsin2x is equal to:
- 2
- 54
- 32
- 3
Q.
Evaluate:
limn→∞1.2+2.3+3.4+...+n(n+1)n3
Q. ___
Evaluate limx→0(x+1)5−1x
Q.
The value of in order that decreases for all real value of is given by
Q. Let f:(0, π)→R be a twice differentiable function such that limt→xf(x)sint−f(t)sinxt−x=sin2x for all x∈(0, π).
If f(π6)=−π12, then which of the following statement(s) is (are) TRUE?
If f(π6)=−π12, then which of the following statement(s) is (are) TRUE?
- f(π4)=π4√2
- f(x)<x46−x2 for all x∈(0, π)
- There exists α∈(0, π) such that f′(α)=0
- f′′(π2)+f(π2)=0