Mean Deviation about Mean for Discrete Frequency Distributions
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Arjun and Karna had an archery competition where they had to shoot a target board with 7 concurrent circles dividing the board into 8 concurrent circular strips. Score for each outcome decreases by unity with centermost circle having score of 8. Dronacharya had difficulty in deciding who the winner was after the scores were recorded. Calculate the mean deviation about the score of innermost circle so as to decide who the winner is, assuming the winner is less deviated from the bull's eye.
Points87654321Arjun(fi)571423111043Karna(fi)58112414853
Arjun
Karna
Both of them
Insufficient data
MarksFrequency0x−21x2x23(x+1)242x5x+1
Where x is positive integer. Then the variance of the marks is
- 1.26
- 1.28
- 1.34
- 1.24
- 710
- 910
- √35
- 45
- Mean =3
- Mean =5
- Variance =3
- Variance =5
Class interval | 5 | 15 | 25 | 35 | 45 |
Frequency | 5 | 3 | 9 | 12 | 6 |
- 10.2
- 10.4
- 10.5
- 11.4
Score (x) | 6 | 20 | 8 | 18 | 16 | 12 | 14 | 10 |
Frequency (f) | 2 | 7 | 11 | 27 | 18 | 13 | 17 | 5 |
- 3.117
- 3.217
- 4.212
- 6.21
Given are the observations of runs scored by batsmen between India - Sri Lanka combined. Find the mean deviation about mean for the scores of batsmen
Score0−1010−2020−3030−4040−5050−60number ofBatsmen12182720176
15
99
10
50
- ∑ni=1(xi−¯X)
- 1n∑ni=1∣∣xi−¯X∣∣
- ∑ni=1(xi−¯X)2
- 1n∑ni=1(xi−¯X)2
- ¯Xσ×100
- ¯Xσ
- σ¯X×100
- σ¯X
- 3
- 9
- 4
- 2
xA2A3A4A5A6Af211111,
where A is a positive integer has a variance of 160, then the value of A is
- 20
- 10
- 10.1
- 20.2
xi2345678fi5234542
is
- 2.3
- 3.4
- 4
- 1.66
Given are the observations of runs scored by batsmen between India - Sri Lanka combined. Find the mean deviation about mean for the scores of batsmen
Score0−1010−2020−3030−4040−5050−60number ofBatsmen12182720176
15
99
10
50
Arjun and Karna had an archery competition where they had to shoot a target board with 7 concurrent circles dividing the board into 8 concurrent circular strips. Score for each outcome decreases by unity with centermost circle having score of 8. Dronacharya had difficulty in deciding who the winner was after the scores were recorded. Calculate the mean deviation about the score of innermost circle so as to decide who the winner is, assuming the winner is less deviated from the bull's eye.
Points87654321Arjun(fi)571423111043Karna(fi)58112414853
Arjun
Karna
Both of them
Insufficient data
Arjun and Karna had an archery competition where they had to shoot a target board with 7 concurrent circles dividing the board into 8 concurrent circular strips. Score for each outcome decreases by unity with centermost circle having score of 8. Dronacharya had difficulty in deciding who the winner was after the scores were recorded. Calculate the mean deviation about the score of innermost circle so as to decide who the winner is, assuming the winner is less deviated from the bull's eye.
Points87654321Arjun(fi)571423111043Karna(fi)58112414853
Arjun
Karna
Both of them
Insufficient data
Steven Gerard, arguably one of the most consistent and skilled player in English premier league was given monthly ratings by a Football website. The ratings are given on monthly basis. The following are the ratings for the past 40 months.
Rating688.59710Number of months with the rating2810785
Calculate how his rating is deviating from his average performance in terms of mean deviation about mean.
0.825
0.85
0.9
1
xi2345678fi5234542
is
- 2.3
- 3.4
- 4
- 1.66
MarksFrequency0x−21x2x23(x+1)242x5x+1
Where x is positive integer. Then the variance of the marks is
- 1.26
- 1.28
- 1.24
- 1.34
xA2A3A4A5A6Af211111
, where A is a positive integer has a variance of 160, then the value of A is