Median
Trending Questions
Q. Consider the following frequency distribution :
Class:10−2020−3030−4040−5050−60Frequency:α1105430β
If the sum of all frequencies is 584 and median is 45, then |α–β| is equal to
Class:10−2020−3030−4040−5050−60Frequency:α1105430β
If the sum of all frequencies is 584 and median is 45, then |α–β| is equal to
Q. Given the following frequency distribution with some missing frequencies
Class10−2020−3030−4040−5050−6060−7070−80Frequency1803418013650
If the total frequency is 685 and approximate value of median is 42.6, then the approximate values for missing frequencies are
Class10−2020−3030−4040−5050−6060−7070−80Frequency1803418013650
If the total frequency is 685 and approximate value of median is 42.6, then the approximate values for missing frequencies are
- 87, 23
- 82, 24
- 80, 25
- 83, 22
Q.
Find the mean and standard deviation using short-cut method.
xi |
60 |
61 |
62 |
63 |
64 |
65 |
66 |
67 |
68 |
fi |
2 |
1 |
12 |
29 |
25 |
12 |
10 |
4 |
5 |