Non Removable Discontinuities
Trending Questions
Findlimx→ 0+sgn(x)+limx→ 0−sgn(x), where sgn(x) represents the signum function
I. The range of f is a closed interval.
II. f is continuous on R.
III. f is one-one on R
- I only
- II only
- III only
- None of I, II and III
- 3
- 2
- Does not exist
- 1
- (1225, 925)
- (1225, −925)
- (1625, −825)
- (2425, −725)
- 1
- 2
- 3
- 4
The given graph is discontinuous at x=a because the limit doesn't exist at x=a
True
False
- 2
- 4
- −3
- 3
(where [.] represents greatest integer function)
- f(x) has missing point discontinuity.
- f(x) has isolated point discontinuity.
- f(x) has finite type discontinuity.
- f(x) has infinite type discontinuity.
Let f(x)={x[1x]+x[x]if x≠00if x=0 where [⋅] denotes the greatest integer function, then which of the following is true?
f(x) has a removable discontinuity at x=1
f(x) has a non- removable discontinuity at x=2.
f(x) is discontinuous at all positive integers.
None of these
- f(x) is continuous at x = 0
- None of these
- limx→0+f(x)=1
- limx→0−f(x)=1
limx→0(3x+|x|7x−5|x|)=
16
37
2
does not exist
In which of the following cases is the function f(x) discontinuous at a?
- −1≤x≤1
- −32≤x≤−1
- −32≤x≤32
- −1≤x≤32
- 1
- −0.5
- 0.5
- 1.5
Let f(x)={x[1x]+x[x]if x≠00if x=0 where [⋅] denotes the greatest integer function, then which of the following is true?
f(x) has a removable discontinuity at x=1
f(x) has a non- removable discontinuity at x=2.
f(x) is discontinuous at all positive integers.
None of these
Consider the following statements:
Then which of the above statement(s) is correct:
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
List - I | List - II |
A) f′(a)=0 and f′′(a)<0 then | l) f(x) is increasing at x=a |
B) f′(a)=0 and f′′(a)>0 then | 2) f(x) has maximum value at x=a |
C) f′(a)≠0 then | 3) f(x) has neither maximum nor minimum |
D) f′(a)>0 | 4) f(x) has minimum value at x=a |
5) f(x) is decreasing at x=a |
- A -4, B -2, C -3, D -5.
- A -2, B -4, C -3, D -1.
- A -2, B -4, C -3, D -5.
- A -2, B -4, C -5, D -1.
f(x)=[x] is discontinuous at x=1 because
Value of function is not defined
Value of f(x) is finite but not equal to the limit
Limit doesn't exist
Statement wrong, function is continuous
limx→0(3x+|x|7x−5|x|)=
16
37
2
does not exist
f(x)=[x] is discontinuous at x=1 because
Value of function is not defined
Value of f(x) is finite but not equal to the limit
Limit doesn't exist
Statement wrong, function is continuous
- between the lines x=1 and x=2
- between the lines x=1 and x=32
- strictly below the line 4y=1
- none of these
- If f(x) is continuous at x=2, then k=−1
- If f(x) is differentiable at x=2, then k=−1
- f(x) is not differentiable at x=2, for any real value of k
- If k>3, then the least value of f(x) occurs at x=2
f=⎧⎨⎩|x|+[x], −1≤x<1x+|x|, 1≤x<2x+[x], 2≤x≤3,
where [t] denotes the greatest integer less than or equal to t. then, f is discontinuous at:
- four or more points
- only one point
- only three points
- only two points
- limx→4−f(x) exists but limx→4+f(x) does not exist
- limx→4+f(x) exist but limx→4−f(x) does not exist
- f is continuous at x=4
- Both limx→4−f(x) and limx→4+f(x) exist but are not equal
- 0
- 1
- −1
- does not exist