Odd Extension of a Function
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Solve for x
Cos-1[(x2-1)/(x2+1)] + Tan-1[2x/(x2-1)] = 2π/3
(i) tan2x
Odd extension is obtained by replacing x by (-x) in the equation of f(x).
True
False
If f(x) = x3+x2 for 0 ≤x≤2 then the odd extension of f(x) would be -
x +2 for 2 < x ≤ 4
x3 + x2 for -2 ≤ x ≤ 0
f(x) =
x +2 for -4 ≤ x < -2
-x3 + x2 for -2 ≤ x ≤ 0
f(x) =
-x +2 for -4 ≤ x < -2
None of these
x3 - x2 for -2 ≤ x ≤ 0
f(x) =
x -2 for -4 ≤ x < -2
(where [.] denotes greatest integer function)
- -5<P<5
- None of these
- P<5
- P>5
(a) 0
(b) 5
(c) 6
(d) 10
Solve the following equations for x:
(i) tan−12x + tan−13x = nπ +
(ii) tan−1(x + 1) + tan−1(x − 1) = tan−1
(iii)
(iv) sin−1x + sin−12x =
(v)
(vi)
(vii) tan−1(x −1) + tan−1x tan−1(x + 1) = tan−13x
(viii) tan (cos−1x) = sin
(ix) tan−1tan−1x = 0, where x > 0
(x) cot−1x − cot−1(x + 2) = , x > 0
(xi)
(xii) tan−1(x + 2) + tan−1(x − 2) = tan−1, x > 0
(xiii)
- domain of f(x) is R
- domain of f(x) is[-1, 1]
- range of f(x) is (−2π3, π3]
- range of f(x) is R
- None of these
- -5<P<5
- P<5
- P>5
solve: tan-1 (under root x2 +x) +sin-1 (under root x2+x+1) = pie/2 ??
∣∣ ∣ ∣∣AA2BeA+BB2−11A2+B2−1∣∣ ∣ ∣∣=?
- sin θ
- cosec θ
- 0
- 1
- −5<p<5
- p<5
- p>5
- None of these
The odd extension of the function y = x2 is y = −x2
True
False
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Both Assertion and Reason are incorrect
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Both Assertion and Reason are incorrect
Q. ydx +
tan−114+tan−129=12tan−143
a) 0 b) 2 c) 3
d) No solution e) -2/3