Proof by mathematical induction
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If n is a natural number then (n+12)n ≥ n ! is true
when
n > 1
n > 2
1
If r is a fixed positive integer, prove by induction that (r+1)(r+2)(r+3)....(r+n) is divisible by n!
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Prove using mathematical induction that for all n≥1
1+4+7+..+(3n-2)=n(3n−1)2
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Let P(n) denote the statement that n2 + n is odd. It
is seem that P(n) ⇒ P(n + 1), Pn is true for all
n
None of these
n > 1
n > 2
Verify that for all n≥1 , the sum of the squares of the first 2n positive integers is given by the formula 12+22+32+.....(2n)2=n(2n+1)(4n+1)3
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Use the Principle of Mathematical Induction, check if, for any positive integer n, 6n−1 is divisible by 5. True or False?
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For natural number n, 2n(n-1) ! < nn, if
n < 2
n > 2
Never
2
For every positive integral value of n, 3n > n3 when
n > 2
3
4
n < 4