Proof of Rolle's Theorem
Trending Questions
Q. Lef f, g and h be differentiable functions. If f(0)=1, g(0)=2, h(0)=3 and the derivatives of their pairwise products at x=0 are (fg)′(0)=6, (gh)′(0)=4 and (hf)′(0)=5, then the value of (fgh)′(0) is
Q. Let y=f(x) and y=g(x) be two differentiable function in [0, 2] such that f(0)=3, f(2)=5, g(0)=1 and g(2)=2. If there exists atleast one c ϵ (0, 2) such that f′(c)=k g′(c), then k must be
- 2
- 1
- 3
- 12
Q. For all twice differentiable functions f:R→R, with f(0)=f(1)=f′(0)=0,
- f′′(x)=0, at every point x∈(0, 1)
- f′′(x)≠0, at every point x∈(0, 1)
- f′′(x)=0, for some x∈(0, 1)
- f′′(0)=0
Q.
Let f(x) = x + 1; where xϵ[0, ∞]. Choose the right option.
f(x) is discontinuous at but removable
None of these
f(x) is discontinuous at
f(x) is continuous at
Q. Let y=f(x) and y=g(x) be two differentiable function in [0, 2] such that f(0)=3, f(2)=5, g(0)=1 and g(2)=2. If there exists atleast one c ϵ (0, 2) such that f′(c)=k g′(c), then k must be
- 2
- 3
- 12
- 1
Q. Let y=f(x) and y=g(x) be two differentiable function in [0, 2] such that f(0)=3, f(2)=5, g(0)=1 and g(2)=2. If there exists atleast one c ϵ (0, 2) such that f′(c)=k g′(c), then k must be
- 2
- 3
- 12
- 1
Q. Let y=f(x) and y=g(x) be two differentiable function in [0, 2] such that f(0)=3, f(2)=5, g(0)=1 and g(2)=2. If there exists atleast one c ϵ (0, 2) such that f′(c)=k g′(c), then k must be
- 2
- 3
- 12
- 1