Properties of Orthogonality of Two Circles
Trending Questions
- Radius of S is 8
- Radius of S is 7
- Centre of S is (-7, 1)
- Center of S is (-8, 1)
Find the equation of the circle orthogonal to the circles x2+y2+3x−5y+6=0 and 4x2+4y 2−28x+29=0 and whose center lies on the line 3x + 4y + 1 = 0.
x2 + y2 + y/4 - 29/4 = 0
2x2 + 2y2 + y - 29 = 0
8x2 + 8y2 + 2y - 29 = 0
4x2 + 4y2 + 2y - 29 = 0
If a circle passes through the point (1, 2) and cuts the circle x2+y2=4 orthogonally, then the equation of the locus of its centre is
2x + 4y - 1 = 0
2x + 4y - 9 = 0
- x2−y2−5x−9y−26=0
- x2−y2−5x−9y+26=0
- x2+y2+5x−y−14=0
- x2+y2+5x+y+14=0
- −2
- −4
- −12
- −1
- ad+be = c+f
- 2ad+2be = c+f
- a+b+c = d+e+f
- Radius of S is 8
- Radius of S is 7
- Centre of S is (-7, 1)
- Center of S is (-8, 1)
- the value of c cannot be determined
- no such circle is possible
- there is a unique value of c
- the value of c depends upon g and f
- (0, −6)
- (−6, 6)
- (0, 0)
- (−6, 0)
- 203 sq. units
- 163 sq. units
- 103 sq. units
- 143 sq. units
- (9/8, 9/2)
- (2, −4)
- (−9/8, 9/2)
- (2, 4)
- 12
- −12
- 23
- √2
Two circles x2+y2+2g1x+2f1y+c1=0 and x2+y2+2g2x+2f2y+c2=0 are said to be orthogonal. Then 2g1g2+2f1f2=c1+c2
True
False
- R−{√n, n≥0, n∈I}
- R
- R−0
- R−{±√n, n∈N}
- (3/2, 1/2)
- (1/2, 3/2)
- (1/2, −21/2)
- (1/2, 21/2)
II. If the points (1, −6), (5, 2), (7, 0), (−1, k) are concyclic then k=−3.
- Only I is true
- Only II is true
- I & II are true
- Neither I & II are true
- √8
- 4
- 16
- √36
- 35
- 23
- 1√2
- 12
Two circles x2+y2+2g1x+2f1y+c1=0 and x2+y2+2g2x+2f2y+c2=0 are said to be orthogonal. Then 2g1g2+2f1f2=c1+c2
True
False
- 32
- 12
- 23
- 54
- a+b+c = d+e+f
- ad+be = c+f
- 2ad+2be = c+f
- a+b+c = d+e+f
- ad+be = c+f
- 2ad+2be = c+f
Find the equation of the circle orthogonal to the circles x2+y2+3x−5y+6=0 and 4x2+4y 2−28x+29=0 and whose center lies on the line 3x + 4y + 1 = 0.
x2+y2+y4−294=0
2x2+2y2+y−29=0
8x2+8y2+2y−29=0
4x2+4y2+2y−29=0
x2+y2−9x+14=0
and x2+y2+15x+14=0
orthogonally and passes through the point (2, 5).