Slope Formula for Angle of Intersection of Two Curves
Trending Questions
- tanθ±secθ=3t
- Coordinates of Q is (−13, −23)
- Angle between tangents at P and Q is π2
- Angle between tangents at P and Q is π4
The angle between the pair of straight lines formed by joining the points of intersection of and to the origin is a right angle. Then, is equal to
complementary then the locus of the point of intersection of the tangents is
x2a2−y2b2=1 and A′ be the farther vertex. If
ΔA′LL′ is equilateral, then the eccentricity of the hyperbola is
- e⎛⎝11−e⎞⎠
- e−1e
- 1e−1
- e⎛⎝1e−1⎞⎠
[Roorkee 2000; Karnataka CET 2001]
- tan−1(43)
- tan−1(1)
- 90o
- tan−1(34)
- (4(¯z1)+1(¯z2)+1(¯z3))(4(¯z1)+1(¯z2)+1(¯z3))=9
- Complex number (z1+z2+z3)/3 will be on the curve |z|=1
- arg(z2z3)=2π3
- Orthocentre and circumcenter of Δ PQR will coincide
[Karnataka CET 1999]
- tan−1(3)
- tan−1(2)
- π2
- π4
Which of the following gives the length of subtangent ?
[PT = length of tangent, (x1, y1) is the point where the tangent is drawn, θ is the angle the tangent makes with x-axis, x1, y1, PT > 0]
PT cos θ
- −1
- 0
- 1
- 2
- x+3y−62=0
- x−3y−11=0
- x−3y+22=0
- x+3y+26=0
[Karnataka CET 1999]
- tan−1(3)
- tan−1(2)
- π2
- π4
f(x) and g(x) intersect at (3, 5). If given that f’(3) = 7 and g’(3) = -1 then find the angle of intersection between f(x) and g(x) at (3, 5)
- θ=tan−1(4/3)
- θ=tan−1(3/4)
- θ=tan−1(5/3)
- None of these
List - I | List - II |
A. cotαcotβ=k , locus of P is | 1. kx=a |
B. tanα+tanβ=k , locus of P is | 2. y=k(x−a) |
C. tan(α+β)=k locus of P is | 3. kx=y |
D. tanαtanβ=k , locus of P is | 4. xy=k |
5. x=ka |
- A−5, B−3, C−1, D−2
- A−1, B−3, C−2, D−4
- A−3, B−2, C−1, D−5
- A−4, B−2, C−1, D−5
- Independent of x
- Independent of y
- Independent of x but dependent on y
- Independent of y but dependent on x
f(x) and g(x) intersect at (3, 5). If given that f’(3) = 7 and g’(3) = -1 then find the angle of intersection between f(x) and g(x) at (3, 5)
- θ=tan−1(3/4)
- θ=tan−1(4/3)
- θ=tan−1(5/3)
- None of these
[Roorkee 2000; Karnataka CET 2001]
- tan−1(43)
- tan−1(1)
- 90o
- tan−1(34)
[Karnataka CET 1999]
- tan−1(3)
- tan−1(2)
- π2
- π4
f(x) and g(x) intersect at (3, 5). If given that f’(3) = 7 and g’(3) = -1 then find the angle of intersection between f(x) and g(x) at (3, 5)
- θ=tan−1(4/3)
- θ=tan−1(3/4)
- θ=tan−1(5/3)
- None of these
- Independent of x
- Independent of y
- Independent of x but dependent on y
- Independent of y but dependent on x
- 0
- −1
- 12
- 2
[Roorkee 2000; Karnataka CET 2001]
- tan−1(43)
- tan−1(1)
- 90o
- tan−1(34)
f(x) and g(x) intersect at (3, 5). If given that f’(3) = 7 and g’(3) = -1 then find the angle of intersection between f(x) and g(x) at (3, 5)
None of these
θ = tan-1 (3 / 4)
θ = tan-1 (5 / 3)
θ = tan-1 (4 / 3)