Standard Deviation about Mean
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6, 10, 7, 13, a, 12, b, 12 are 9 and 374 respectively, then (a−b)2 is equal to
- 32
- 12
- 24
- 16
- 7
- 1
- 11
- 9
The mean of the numbers a, b, 8, 5, 10 is 6 and the variance is 6.80. Then which one of the following gives possible values of a and b?
a=0, b=7
a=5, b=2
a=1, b=6
a=3, b=4
x:x1=2x2=6x3=8x4=9f:44αβ
be 6 and 6.8 respectively. If x3 is changed from 8 to 7, then the mean for the new data will be
- 5
- 4
- 173
- 163
- 4
- 2
- 2√2
- √2
- 380
- 400
- 480
- 525
- (11, 25)
- (11, 26)
- (10.5, 25)
- (10.5, 26)
- 53625
- 1345
- 1125
- 925
- 9
- 81
- 7
- 90
- 1, 20
- 10, 11
- 3, 18
- 8, 13
A student is allowed to select at most n books from a collection of books. If the total number of ways in which he can select at least one book is , then the value of n is equal to
- 5
- 6
- 4
- 8
- 4:9
- 5:8
- 10:3
- 6:7
- 20
- 16
- 18
- 22
- 20
- 50
- 10
- 15
The mean and standard deviation of 6 observations are 8 and 4 respectively. If each observation is multiplied by 3, find the new mean and new standard deviation of the resulting observations.
- √6
- 2√103
- 2√6
- 4√53
([⋅] represents the greatest integer function)
If are observations such that and , then the standard deviation of these observations is
- 3a2−32a+84=0
- 3a2−34a+91=0
- 3a2−23a+44=0
- 3a2−26a+55=0
- 3
- 9
- 7
- 5
- 4
- 2
- 2√2
- √2
- 1
- 3
- 5
- 7
- 27912
- 1332
- 3994
- 1334
The standard deviation of 4 consecutive numbers which are in A.P is √5. The common difference (d) of this A.P is
±√5
±2√5
±2
±√2
- λσ
- λσ
- |λ|σ
- λnσ