Standard Equation of Ellipse
Trending Questions
- x210+y25√3=1
- x225+y2100=1
- x275+y2100=1
- x210+y225=1
- −1+√62
- −1+√82
- −1+√32
- −1+√52
- x220+y216=1
- x218+y213=1
- x225+y220=1
- x225+y216=1
Let P be a variable point on the ellipse x2a2+y2b2=1 with foci F1 and F2. If A is the area of the ΔPF1F2, then the maximum value of A is
b√a2−b2
- b√b2−a2
- a√a2−b2
- a√b2−a2
- the maximum value of ab is 23
- a∈(√25, 2)
- a∈(23, 2)
- the maximum value of ab is 1
- −13
- −49
- −19
- −29
Find the equation of the ellipse whose foci are (4, 0) and (-4, 0), eccentricity = 1/3.
- 2p2+q2
- p2+4q2
- 4p2+q2
- p2+2q2
An ellipse is drawn by taking the diameter of the circle as its semi-minor axis and the diameter of the circle as the semi-major axis, if the center of the ellipse at the origin and its axis are the coordinates axes, then the equation of the ellipse is
- (±√7, ±94)
- (±√9, ±165)
- (±4, ±254)
- (±6, ±45)
- 4x2+3y2−18x−24y+47=0
- 3x2+4y2+18x−24y−47=0
- 3x2+4y2−18x−24y+47=0
- 3x2+4y2−24x−18y+47=0
Equation of the latus rectum of the ellipse
- 14
- 8
- 12
- 7
- centre is (1, 2)
- eccentricity is 45
- end points of latus-rectum are (5, 195) and (5, 15)
- length of major axis will be 10 units
If a vector →r has magnitude 14 and direction ratios 2, 3 and -6. Then, find the direction cosines and components of →r, given that →r makes an acute angle with X- axis.
One of the points on the parabola with focal distance is
- a2x1y1
- a2y1x1
- 2a2
- 4a2
If the line x+2y+4=0 cutting the ellipse x2a2+y2b2=1 in points whose eccentric angles are 30∘ and 60∘ subtends a right angle at the origin then its equation is
none of these
x28+y24=1
x216+y24=1
x24+y216=1
- √2
- √3
- 2√3
- 3√2