Vectorial Representation of a Complex Number
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Express the following complex numbers in the standard form a + i b :
(i) (1+i)(1+2i)(ii) 3+2i−2+i(iii) 1(2+i)2(iv) 1−i1+i(v) (2+i)32+3i(vi) (1+i)(1+√3i)1−i(vii) 2+3i4+5i(viii) (1−i)31−i3(ix) (1+2i)−3(x) 3−4i(4−2i)(1+i)(xi) (11−4i−21+i)(3−4i5+i)(xii) 5+√2i1−√2i
- 5π6
- π6
- π3
- −5π6
If , then is equal to
If and are different real numbers and and are position vectors of three non-collinear points, then?
centroid of is
is not equally inclined to three vectors
is a scalene triangle
perpendicular from the origin to the plane of the triangle does not meet it at the centroid
Column IColumn II(A)|z−z1|=k|z−z2|, k>0(p)Circle(B)||z−z1|−|z−z2||=k1, k1∈R(q)Line(C)|z+z1|+|z+z2|=k2, k2>0(r)Ellipse(D)arg(z−z1z−z2)=α, α∈R(s)No locus(t)Hyperbola
- A(P, Q), B(Q, S, T), C(Q, R, S), D(P, Q)
- Option d
- Option a
- Option b
limx→2x2−4√3x−2−√x+2
- lx+my+nz=p(x2+y2+z2)
- lx+my+nz=x2+y2+z2
- p(lx+my+nz)=x2+y2+z2
- None of these
Locus of point z so that z, i, and iz are collinear, is
A straight line
An ellipse
A circle
A rectangular hyperbola
- π3
- 5π6
- −5π6
- π6
A man walks a distance of 3 units, from the origin towards the north - east (N45∘E) direction. From there, he walks a distance of 4 units towards the north - west (N45∘E) direction to reach a point P. Then the position of P in the Argand plane is:
3eiπ/4+4i
(3−4i)eiπ/4
(4+3i)eiπ/4
(3+4i)eiπ/4
- 2√5
- 5√2
- 8
- 11
(xii) 5+√2i1−√2i
- 2(ˆi−ˆj+ˆk)
- 2(ˆi+ˆj+ˆk)
- 2ˆi+ˆj−2ˆk
- 2(−ˆi+ˆj−ˆk)
- −13^i+11^j+7^k
- 13^i−11^j−7^k
- 7^i+13^j+11^k
- 11^i+13^j+9^k
- 1
- 16
- 16ω2
- −325
Locus of point z so that z, i, and iz are collinear, is
A straight line
A circle
An ellipse
A rectangular hyperbola
- n2−n+22
- n2+n+22
- n2−n−12
- n2+n−22
- n2+n−12
(1+i)−1
A man walks a distance of 3 units, from the origin towards the north - east (N45∘E) direction. From there, he walks a distance of 4 units towards the north - west (N45∘E) direction to reach a point P. Then the position of P in the Argand plane is:
POQis a straight line through the origin O, P and Q represent the complex numbers a+ib andc+id respectively and OP=OQ, then
None of these
arg(a+ib)=arg(c+id)
a+c=b+d
(vi) (1+i)(1+√3i)1−i