f(x) Transforms to Its Inverse
Trending Questions
Q.
A line meets the co-ordinate axes in A & B, a circle is circumscribed about the triangle OAB. If d1 and d2 are the distances of the tangent to the circle at the origin O from the points A and B respectively the diameter of the circle is:
Q. The maximum area of a rectangle whose two vertices lie on the x-axis and two on the curve y=3−|x| , −3≤x≤3 , is
- 9
- 3
- 94
- 92
Q. The graph of the function y=f(x) is symmetrical about line x=2, then
- f(x)=f(−x)
- f(2+x)=f(2−x)
- f(2)=f(2−x)
- f(2+x)=f(x−2)
Q.
The graph of the function y=f(x) is symmertical about the line x=2 , then
f(x) = -f(-x)
f(2+x) =f(2-x)
f(x) = f(-x)
f(x + 2) = f(x=2)
Q. The area bounded by y=−|x|+3, x=0, y=0 and x=2, is
- 72 sq. units
- 112 sq. units
- 6 sq. units
- 4 sq. units
Q. The two points on the line 2x + 3y + 4 = 0 which are at distance 2 unit from the line 3x + 4y - 6 = 0 are
- (-8, -8) and (-16, -16)
- (-44, 64) and (-5, 2)
- (-5.5, 1) and (-5, 2)
- (64, -44) and (4, -4)
Q. Let f(x)=min{x+1, √1−x}, then the area bounded by y=f(x) and x-axis is:
- 56
- 16
- 76
- 116
Q. Area of the region {(x, y)∈R2:y≥√|x+3|, 5y≤x+9≤15} is equal to
- 16
- 43
- 32
- 53
Q. The graph of the function y=f(x) is symmetrical about the line x=2. Then,
- f(x+2)=f(x−2)
- f(2+x)=f(2−x)
- f(x)=−f(−x)
- f(x)=f(−x)
Q. If length of perpendicular from origin to line xa+yb=1 is p, then prove that
1p2=1a2+1b2 ?
1p2=1a2+1b2 ?
Q. The equation of line passing through (3, −1, 2) and perpendicular to the lines
¯¯¯r=(^i+^j−^k)+λ(2^i−2^j+^k) and ¯¯¯r=(2^i+^j−3^k)+μ(^i−2^j+2^k) is
¯¯¯r=(^i+^j−^k)+λ(2^i−2^j+^k) and ¯¯¯r=(2^i+^j−3^k)+μ(^i−2^j+2^k) is
- x+32=y+13=z−22
- x−33=y+12=z−22
- x−32=y+13=z−22
- x−32=y+12=z−22
Q. Find the direction cosines l, m, n of a line which are connected by the relation l+m−n=0 and 2ml−2mn+nl=0
- −2√6, 1√6, −1√6
- 2√6, −1√6, 1√6
- −2√6, −1√6, −1√6
- 2√6, 1√6, 1√6
Q. The number of lines that can be drawn through the point (4, −5) at distance of 12 units from the point (−2, 3) is
- 0
- 1
- 2
- infinite
Q. The graph of y=f(x) is symmetrical about the line x=1, then
- f(−x)=f(x)
- f(1+x)=f(1−x)
- f(x+1)=f(x−1)
- None of these
Q. In given figure trapezoid ABCD is graphed in the standard (x, y) coordinate plane. Which of the following vertical line cuts ABCD into 2 trapezoids with equal areas
- x=2.5
- x=3.5
- x=4.5
- x=6.5
- x=5.5
Q. Find the area under the curve y=√6x+4 above x-axis from x=0 to x=2.
Q. Draw the graph of the following function given by ⎧⎨⎩x|x|ifx≠00ifx=0
Q. The graph of the function y=f(x) is symmetrical about line x=2, then
- f(x)=f(−x)
- f(2+x)=f(2−x)
- f(2)=f(2−x)
- f(2+x)=f(x−2)
Q. The area bounded by y=−|x|+3, x=0, y=0 and x=2, is
- 72 sq. units
- 4 sq. units
- 112 sq. units
- 6 sq. units
Q. The area bounded by y=−|x|+3, x=0, y=0 and x=2, is
- 72 sq. units
- 4 sq. units
- 112 sq. units
- 6 sq. units
Q. Square OABC is drawn with vertex O as origin, vertex A on the positive side of x−axis and vertex C on the positive side of y-axis. If each side of the square OABC is of length 6 units, draw OABC on a graph paper and then use the graph to find the co-ordinates of vertices A, B and C.
Q. The number of lines that can be drawn through the point (4, −5) at a distance 12 from the point (−2, 3) is :
- 0
- 1
- 2
- Infinite
Q. The graph of the function y=f(x) is symmetrical about line x=2, then
- f(x)=f(−x)
- f(2+x)=f(2−x)
- f(2)=f(2−x)
- f(2+x)=f(x−2)
Q. On the graph above, when x=12, y=2 and when x=1, y=1. The graph is symmetric with respect to the vertical line at x=2. According to the graph, when x=3, y=
- −1
- −12
- 0
- 12
- 1