2D Collision Example
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In the figure shown below, two identical balls of mass M and radius R each, are placed in contact with each other on the frictionless horizontal surface. The third ball of mass M and radius R/2, is coming down vertically and has a velocity v0 when it hits the two balls symmetrically and itself comes to rest. Then, each of the two bigger balls will move after collision with a speed equal to
- 4v0√5
- 2v0√5
- v0√5
- √5v0
A hunter aims his gun and fires a bullet directly at a monkey on a tree. At the instant the bullet leaves the barrel of the gun, the monkey drops. Will the bullet hit the monkey? Substantiate (give proper evidence to prove the truth of) your answer with proper reasoning.
The track shown in figure (9-E16) is frictionless. The block B of mass 2m is lying at rest and the block A of mass m is pushed along the track with some speed. the collision between A and B is perfectly elastic. With what velocity should the block A be started to get the sleeping man awakened ?
- HRu(R2+4H2)√R2+16H2
- 4HRu(R2+4H2)√R2+16H2
- uH
- uR(H)√R2+16H2
A ball collides elastically with another ball of the same mass. The collision is oblique and initially second ball was at rest. After the collision, the two balls move with same speeds. What will be the angle between the velocities of the balls after the collision?
- Less than
- More than
- Exactly
- Exactly
[Assume, there is no friction between the two blocks]
- √53 m/s
- √73 m/s
- √83 m/s
- √103 m/s
- 32.5 J
- 46.875 J
- 49.375 J
- 0 J
In an ……. collision, the kinetic energy before collision is equal to the kinetic energy after collision.
- −√2^i+√2^j
- √2^i−√2^j
- √2^i+√2^j
- −√2^i−√2^j
- 4.9 m
- 13.3 m
- 9.1 m
- 12.6 m
- R2=2h1h2
- R2=h1h2
- R2=16h1h2
- R2=4h1h2
diagram
- tan−1(5√3)
- sin−1(5√28)
- tan−1(√328)
- sin−1(√328)
- √k2
- √3k2
- √5k2
- √7k2
A projectile is thrown with a velocity vat an angle a with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is
- v sin a * 3
- vsin a / 3
- vsin a / root 2
- 1
- 16
- 13
- 1√3
- 46.875 J
- 0 J
- 32.5 J
- 49.375 J
- v1−v2=2v1
- θ2−θ1=2θ1
- v1=v2
- 3(θ2−θ1)=+θ1
- Kinetic energy
- Momentum
- Temperature
- Both (a) and (b)
- The component of the momentum of system perpendicular to the line of impact is conserved.
- The component of the momentum of each ball separately perpendicular to the line of impact is conserved.
- Both (a) and (b) are correct.
- Both (a) and (b) are incorrect.
- The kinetic energy of each body remains constant.
- The initial kinetic energy is greater than the final kinetic energy.
- The initial kinetic energy is equal to the final kinetic energy.
- The initial kinetic energy is less than the final kinetic energy.
- The kinetic energy of the A - B system at maximum compression of the spring is zero.
- The kinetic energy of the A - B system at maximum compression of the spring is 100 J.
- The maximum compression of the spring is 1.5 m.
- The maximum compression of the spring is 1 m.
- 2.54 i + 1.62 j
- 2.54 i - 1.62 j
- 1.89 i + 0.83 j
- 1.89 i - 0.83 j
- √20 m/s
- √30 m/s
- √10 m/s
- √40 m/s
- 2.54 i + 1.62 j
- 2.54 i - 1.62 j
- 1.89 i + 0.83 j
- 1.89 i - 0.83 j
- 45√2 ms−1
- 45 ms−1
- 90 ms−1
- 22.5√2 ms−1
- Disc
- Ring
- Solid sphere
- Hollow sphere
- Faster one
- Both will reach simultaneously
- Cannot be predicted
- Slower one