2lambda Paradox
Trending Questions
- βG>βB>βR
- βR>βB>βG
- βR>βG>βB
- βB>βG>βR
- Fringe width will decrease
- Fringe width will increase
- Fringe width will remain unchanged
- Fringe will become less intense
- I=I0cosϕ
- I=I0cos2ϕ
- I=I0(1+cosϕ)
- I=2I0(1+cosϕ)
- 0.3 mm
- 3 mm
- 4 mm
- 0.12 mm
- P−2, Q−2, R−4, S−1
- P−3, Q−3, R−4, S−1
- P−1, Q−3, R−1, S−1
- P−2, Q−3, R−2, S−3
- xdL
- xLd
- Ldx
- xdL+x
- 6×10−6m
- 6.6×10−6m
- 3.138×10−7m
- 3.144×10−7m
- 3
- 4
- 2
- 5
In a young's doube slit experiment using mono-chromatic light, the fringe pattern shifts by a certain distance on the screen whwen a mica sheet of refractive index 1.6 and thickness 1.964 micron (1micron=10−6m) is introduced in t epath of one of th einterfering waves. The mica sheet is then removed and
the distance between the screen and the slits is doubled. It is found that the distance between teh successive maxima now is the same as the observed fringe- shift upon th eintroduction of the mica sheet. Calculate the wavelength of the monochromatic light used in the experiment.
- 5200
- 4800
- 6200
- 5600
- 0.75 mm
- 0.50 mm
- 1 mm
- 0.25 mm
Find out the minimum order of the bright fringe that would not be visible
- second bright band occurs
- second dark band occurs
- third dark band occurs
- thirdbright band occurs
What is the error in the reasoning?
- The slit is too big.
The resultant of waves from each pair of points are not in the same phase, so they will not interfere constructively.
- Interference will not happen.
- Intensity is not given.
Plane microwaves are incidnet on a long slit having a width of 5.0 cm. Calculate the wavelength of the microwaves if the first diffraction m8inimum is formed at θ=30∘
- 0.36 μm
- 360 μm
- 3.6 μm
- 36 μm
- 2.8mm
- 3.2mm
- 4.0mm
- 4.8mm
What is the error in the reasoning?
It's right, this is a tragedy, the world is gonna get destroyed.
The resultant of waves from each pair of points are not in the same phase, so they will not interfere constructively.
- \N
- \N
- Increases
- Decreases
- Remains Same
- Becomes zero
- all the four will shift in the direction O to C
- the images C, B and A will shift away from O
- all the four will shift in the direction C to O
- the images C, B and A will shift towards O
- Second maxima occurs
- Second minima occurs
- Third minima occurs
- Third maxima occurs
- Increases
- Decreases
- Remains Same
- Becomes zero
- 60∘
- 45∘
- 30∘
- 15∘
- dsinθm=mλ, m=1, 2, 3, ....
- dsinθm=mλ, 2m=1, 2, 3, ....
- dsinθm=(m+1)λ2, m=1, 2, 3, ....
- dsinθm=(m−1)λ2, m=1, 2, 3, ....
- 150MHz
- 170MHz
- 175MHz
- 190MHz
- Increases
- Decreases
- Remains Same
- Becomes zero
- angular frequency
- wave number
- Both options (A) and (B)
- None of these
Find out the minimum order of the bright fringe that would not be visible
Find out the minimum order of the bright fringe that would not be visible