Acceleration for Non Linear Motion
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A rabbit runs across a parking lot on which a set of coordinate axes has, strangely enough, been drawn.
The coordinates (meters) of the rabbit's position as functions of time t (seconds) are given by
x=−t22+5t+20
And y=t2−10t+30
Find the acceleration at time t = 15 s?
- The acceleration of the particle is zero at t=0 second
- The velocity of the particle is zero at t=0 second
- The velocity of the particle is zero at t=1 second
- The velocity and acceleration of the particle are never zero
The x and y coordinates of the particle at any time are x=5t−2t2 and y=10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2 s is
- 5 m/s2
- −4 m/s2
- −8 m/s2
- 0 m/s2
A particle's position in the x-y plane varies as x(t)=3t3+4t2, y(t)=16t4+2
Find the acceleration vector of the particle after 1 sec of start.
18m/s2 ^i+192 m/s2^j
3m/s2 ^i+16 m/s2^j
26m/s2 ^i+192 m/s2^j
7m/s2 ^i+18 m/s2^j
A particle's position in the x-y plane varies as x(t)=3t3+4t2, y(t)=16t4+2
Find the acceleration vector of the particle after 1 sec of start.
A particle's position in the x-y plane varies as x(t)=3t3+4t2, y(t)=16t4+2
Find the acceleration vector of the particle after 1 sec of start.
18m/s2 ^i+192 m/s2^j
3m/s2 ^i+16 m/s2^j
26m/s2 ^i+192 m/s2^j
7m/s2 ^i+18 m/s2^j
A rabbit runs across a parking lot on which a set of coordinate axes has, strangely enough, been drawn.
The coordinates (meters) of the rabbit's position as functions of time t (seconds) are given by
x=−t22+5t+20
And y=t2−10t+30
Find the acceleration at time t = 15 s?
2^i−1^j
1^i+1^j
2^i+2^j
−1^i+2^j