COM of Center of Masses
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- They collide after 2 s.
- They collide after 1 s.
- They collide at a height of 290 m.
- They collide at a height of 280 m.
- (0, 0, 0)
- (3, 1, 8)
- (−1, 2, 3)
- (1, 3, 2)
- 2l3
- l
- 3l2
- 4l3
- 13
- 14
- 16
- 12
- 8 cm from centre of bigger circle to the right.
- 9 cm from centre of bigger circle to the left.
- 10 cm from centre of bigger circle to the left.
- 5 cm from centre of bigger circle to the left.
What is the dimensional formula for the radius of gyration?
- OB
- OA
- OC
- OD
- R20 to the left of A
- R12 to the left of A
- R20 to the right of A
- R12 to the right of A
A steel and a brass wire, each of length 50 cm and cross-sectional area 0.005 cm2 hang from a ceiling and are 15 cm apart. Lower ends of the wires are attached to a light horizontal bar. A suitable downward load is applied to the bar so that each of the wires extends in length by 0.1 cm. At what distance from the steel wire the load must be appied?
[Young's modulus of steel is 2×1012 dynes/cm2] and that of brass is 1×1012 dynes/cm2
- 7.5 cm
- 10 cm
- 3 cm
- 5 cm
- 7.14 cm
- 5.28 cm
- 4 cm
- 6.25 cm
- Inside the circular plate
- Inside the square plate
- At the point of contact
- Outside the system
Four persons K, L, M and N are initially at the corners of a square of side of length d. If every person starts moving, such that K is always headed towards L, L towards M, M is headed directly towards N and N towards K, then the four persons will meet after (assume that they move with a constant speed v)
- (2a3, 2b3)
- (5a12.5b12)
- (3a4.3b4)
- (5a3.5b3)
- (1 cm, 3 cm)
- (2 cm, 2 cm)
- (2.4 cm, 5 cm)
- (3 cm, 6 cm)
- (0, 6.5) m
- (0, 6) m
- (0, 5.28) m
- (0, 4.55) m
- Leftward and downward
- Rightward and downwards.
- Leftward and upwards.
- Only downward.
- a10
- a8
- a12
- a3
- −a7
- 3a7
- −3a7
- −2a7
- 9 cm
- 4.5 cm
- 5.5 cm
- 5 cm
- 4b5
- b3
- b5
- 2b5
- 1.2 cm
- 2.4 cm
- 5.2 cm
- 3.2 cm
- At a distance of 2R from O
- At a distance of 3R from O
- At a distance of 4R from O
- At a distance of 5R from O
- (15l14, 6l7)
- (15l14, l)
- (l, l2)
- (l, l)
- 3.2 cm
- 5.67 cm
- 6.67 cm
- 4.2 cm
In terms of ^i and ^j , find linear velocity of point P.
- 4^i−5^j
- 5^i−4^j
- −5^i−4^j
- 5^i−5^j
- R3
- √3R
- R√3
- R
(Neglect air resistance)
- 3R2
- 4R3
- 5R4
- None of these
- (−6, −6) m
- (−2, 0) m
- (−2, −2) m
- (−6, 0) m
- 2.66 cm
- 6 cm
- 1.66 cm
- 2 cm
- 9√38 m
- 8√3 m
- 9√316 m
- zero