Calculating Friction Using Coeffcients
Trending Questions
- 2 tan θ
- tan θ
- 2 sin θ
- 2 cos θ
- 2 N
- 20 N
- 50 N
- 100 N
- 0.33
- 0.75
- 0.80
- 0.25
- 80 N
- 120 N
- 150 N
- 100 N
- 1.2 m/s2
- 0.2 m/s2
- −1 m/s2
- zero
- cotθ≥μ
- tanθ2≥μ
- tanθ≥μ
- cotθ2≥μ
- 800 m
- 1000 m
- 100 m
- 400 m
The coefficients of static and kinetic friction between a body and the surface are 0.75 and 0.5 respectively. A force is applied to the body to make it just slide with a constant acceleration which is equal to
g4
g2
3g4
g
A boy pushes a box of mass, with a force, on a frictionless surface. If the box was initially at rest, then what is displacement along the -axis after ?
A block of mass 2 kg is on a horizontal surface. The coefficient of static and kinetic friction are 0.6 and 0.2. The minimum horizontal force required to start the motion is applied and if it is continued, the velocity acquired by the body at the end of the 2nd second is?
- μm12
- m12
- μ m1
- 2μ m1
- 8ms−2
- 2ms−2
- 4ms−2
- 6ms−2
A small mass slides down an inclined plane of inclination θ with the horizontal. The coefficient of friction is μ=μ0x, where x is the distance through which the mass slides down, and μ0 a constant. Then, the speed is maximum after the mass covers a distance of
- cos θμ0
- sin θμ0
- tan θμ0
- 2 tan θμ0
A trolley of mass M is attached to a block of mass m by a string passing over a frictionless pulley as shown in the figure. If the coefficient of friction between the trolley and the surface below is μ, what is the acceleration of the trolley and the block system when they are released?
(m−Mm+M)g
mMg
(μm−Mm+M)g
(m−μMm+M)g
- 0.55
- 0.75
- 0.70
- 0.65
Consider a uniform cubical box of side on a rough floor that is to be moved by applying minimum possible force at a point above its centre of mass (see figure). If the coefficient of friction is , the maximum value of for the box not to topple before moving is .
A block of mass m is placed on another block of mass M, which itself is lying on a horizontal surface. The coefficient of friction between two blocks is μ1 and that between the block of mass M and horizontal surface μ2. What maximum horizontal force can be applied to the lower block so that the two blocks move without separation?
(M+m)(μ2−μ1)g
(M+m)(μ2−μ1)g
(M−m)(μ2+μ1)g
(M+m)(μ2+μ1)g
An object of mass is sliding with a constant velocity of on a frictionless horizontal table. The force required to keep the object moving with the same velocity is
32 N
0 N
2 N
8 N
Two blocks of masses m1=4 kg and m2=6 kg are connected by a string of negligible mass passing over a frictionless pulley as shown in the figure. The coefficient of friction between block m1 and the horizontal surface is 0.4. When the system is released, the masses m1 and m2 start accelerating. What additional mass m should be placed over mass m1 so that the masses (m1+m) slide with a uniform speed?
9 kg
10 kg
11 kg
12 kg
[Take g=10 m/s2]
(Assume there is no slipping between the blocks).
- 53 N
- 103 N
- 2 N
- 0 N
- 10√3
- √310
- 0.47
- 0.185
- 4g3
- g3
- g2
- 3g4
- if μ1=0.5 and μ2=0.3, then 5 kg block exerts 3 N force on the 3 kg block
- if μ1=0.5 and μ2=0.3, then 5 kg block exerts 8 N force on the 3 kg block
- if μ1=0.3 and μ2=0.5, then 5 kg block exerts 1 N force on the 3 kg block
- if μ1=0.3 and μ2=0.5, then 5 kg block exerts no force on the 3 kg block