Centripetal Acceleration
Trending Questions
- 2π√lg
- 2π ⎷lg+qEm
- 2π ⎷lg−qEm
- 2π ⎷l√g2+(qEm)2
One end of a string of length l is connected to a particle of mass m and the other to a small peg on a smooth horizontal table. If the particle moves in a circle with speed v the net force on the particle (directed towards the centre) is:
(i) T,
(ii) T−mv2l
(iii) T+mv2l
(iv) 0
T is the tension in the string. [Choose the correct alternative].
- 1:√2
- 1:2
- 1:2√2
- 1:4
- 1:4
- 1:2
- 2:1
- 4:1
- grμ
- √grμ
- √2grμ
- √gr2μ
A ball of mass 0.1 Kg. is whirled in a horizontal circle of radius 1 m. by means of a string at an initial speed of 10 R.P.M. Keeping the radius constant, the tension in the string is reduced to one quarter of its initial value. The new speed is
5 r.p.m.
14 r.p.m.
10 r.p.m.
20 r.p.m.
Two bodies of mass 10 kg and 5 kg moving in concentric orbits of radii R and rsuch that their periods are the same. Then the ratio between their centripetal acceleration is
R2r2
r2R2
Rr
rR
- 10−3 rad/s
- 1 rad/s
- 10−1 rad/s
- 10−5 rad/s
Find the maximum velocity for skidding for a car moved on a circular track of radius 100 m. The coefficient of friction between the road and tyre is 0.2
0.14 m/s
14 m/s
140 m/s
1.4 km/s
A body of mass 1 kg tied to one end of string is revolved in a horizontal circle of radius 0.1 m with a speed of 3 revolution/sec, assuming the effect of gravity is negligible, then linear velocity, acceleration and tension in the string will be
1.88 m/s, 35.5 m/s2, 35.5 N
None of these
2.88 m/s, 45.5 m/s2, 45.5 N
3.88 m/s, 55.5 m/s2, 55.5 N
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