Charges on Large and Parallel Conducting Plates
Trending Questions
- The intensity of electric field between the plates decreases and charge on plates also decreases
- The intensity of electric field between the plates remains constant but charge on the plates increases
- The intensity of electric field between the plates remains constant but charge on the plates decreases
- The intensity of electric field between the plates increases but charge on the plates decreases
- 30∘ from x-axis
- 45∘ from x-axis
- 60∘ from x-axis
- none of these
In an electric field an electron is kept freely . if the electron is replaced by a proton what will be the relationship between the forces experienced by them
(Assume that charges (+q) form vertices of equilateral triangle)
- kq2√3Rm
- ⎷kq2Rm(2−1√3)
- √kq2Rm(√2+1)
- kq22Rm
- Mass of each body remains unchanged
- Mass of positively charged body slightly increases
- Mass of negatively charged body slightly decreases
- Mass of each body changes slightly but the total mass of system remains the same
Two protons A and B are placed in between the two plates of a parallel plate capacitor charged to a potential difference V as shown in the figure. The forces on the protons due to capcitor plates are
- Equal in magnitude and opposite in direction
Equal in magnitude and in same direction
Unequal in magnitude and opposite in direction
Unequal in magnitude and different in direction
(Charge on proton is 1.6×10−19 C and mass of proton is 1.6×10−27 kg)
- 4 μs
- 2 μs
- 2√2 μs
- 4√2 μs
[Given the value of relative permitivity of material (k=50)]
- 9.0 μA
- 0.9 μA
- 0.9 mA
- 9.0 mA
Reason(R): Electric field at all points on gaussian surface is depends only on charges q1 and q2
Select the most appropriate answer from the options given below
- Both A and R are true and R is the correct explanation of A
- Both A and R are true but R is not the correct explanation of A
- A is true but R is false
- A is false and R is also false
- 4kqπR2(^i)
- 4kqπR2(−^i)
- 2kqπR2(−^i)
- 4kqπR(−^i)
- KQ3√3R2
- 2KQ√3R2
- 2KQ3√3R2
- 2KQ√3R2
Force acting upon a charged particle kept between the plates of a charged condenser is F. If one plate of the condenser is removed, then the force acting on the same particle will become:
0
F/2
F
2F
If the potential difference between the plates of a capacitor is increased by 20%, the energy stored in the capacitor increases by exactly
40%
22%
44%
20%
Three identical plates are given charges as shown in figure. Charge flown through switch from middle plate when it is closed is.
- 3Q
- −2Q
- 2Q
- 0
[0.77 Mark]
- Ellipse
- Hyperbola
- Parabola
- Straight Line
(Assume the straight parts of wire perpendicular to XY plane.)
- qλ2πϵ0mR^j
- qλπϵ0mR(−^j)
- 2qλπϵ0mR(^k)
- qλ2πϵ0mR(−^j)
- 2π√md2kλq
- 2π√md23kλq
- π√md22kλq
- 2π√md22kλq
- CVε0
- 2CVε0
- Zero
- CV2ε0
- 3.26×10−11 T
- 1.63×10−11 T
- 4.89×10−11 T
- 8.15×10−11 T
Here graphs(A, B, C, D) corresponding to four charges are shown. Which graph represents the charge of higher magnitude?
- A
- B
- C
- D
- 90 N/C along OC
- 90 N/C along OD
- 180 N/C along OC
- 180 N/C along OD
- −1 nC
- −2 nC
- −3 nC
- −4 nC
According to the principle of conservation of charge, the net change in an isolated system ____________
- ba
- b2a2
- √ba
- ln(ba)
[Assume both sheets have same charge density]
- 3.1×10−13 C/m2
- 4.1×10−13 C/m2
- 5.1×10−13 C/m2
- 6.1×10−13 C/m2
- Terminal velocity of the rod, VT=2FRB2l2
- Terminal velocity of the rod, VT=FRB2l2
- Maximum charge on the capacitor, qmax=FCRBl
- Maximum charge on the capacitor, qmax=2FCRBl