Communication satellite link
Trending Questions
Q. A T.V. transmission tower has height of 80 m. Radius of earth is 6400 km. What is the coverage range of tower?
- 10 km
- 12 km
- 32 km
- 64 km
Q. T.V. transmission tower at a particular station has a height of 160m:(a) What is its coverage range? (b) How much population is covered by transmission, if the average population density around the tower is 1200km−2? (c) By how much the height of tower be increased to double its coverage range? Given radius of earth = 6400km.
- (a) 15255m(b) 87.24m(c) 480m
- (a) 45255m(b) 77.24m(c) 480m
- (a) 35255m(b) 77.24m(c) 280m
- (a) 25255m(b) 97.24m(c) 180m
Q. T.V. tower has a height 100m. What is the population density around the T.V. tower if the total population covered is 50 lac? Radius of earth = 6.4×106m.
- 3242.9k/m2
- 2242.9k/m2
- 4242.9k/m2
- 1242.9k/m2
Q. A TV tower has a height of 75 m. The maximum distance and area up to which this TV transmission can be received is
(Radius of the Earth = 6400 km)
- 31 km, 3018 km2
- 30 km, 3000 km2
- 28 km, 2800 km2
- 25 km, 2500 km2
Q. A T.V. tower at a height of 10 m is in a region of average population density 100π/km2. The number of people that can receive the transmission is nearly
- 1, 28, 000
- 2, 56, 000
- 64, 000
- 32, 000
Q. Some of the important communication channels are
- air
- transmission line
- free space
- any of the above
Q. A long metal bar of 30cm length is aligned along a north south line and moves eastward at a speed of 10ms−1. A uniform magnetic field of 4.0T points vertically downwards. If the south end of the bar has a potential of 0V, the induced potential at the north end of the bar is:
- +12V
- −12V
- 0V
- cannot be determined since there is not closed circuit
Q. A TV tower is 120 m high. How much more height is to added to it, if its coverage range is to become double?
- 120 m
- 240 m
- 360 m
- 480 m
Q. Intensity of electric field obtained at receiver antenna for a space wave propagation is
- directly proportional to the perpendicular-distance from transmitter to antenna
- inversely proportional to the perpendicular-distance from transmitter to antenna
- directly proportional to the square perpendicular distance from transmitter to antenna
- inversely proportional to the square perpendicular distance from transmitter to antenna
Q. At certain distance from a transmitting tower, a receiver tower of height 20 m is used to receive direct signal. Another tower is installed beyond the first, along the same line of sight to receive the signals from the same transmitter. Its height is 44% more than the first receiving tower. Then, the separation between the two receiving towers is (Radius of Earth = 6400 km)
- 6.4 km
- 3.2 km
- 1.6 km
- 0.8 km
Q. A radio receiver antenna that is 2 m long is oriented along the direction of the electromagnetic wave and receives a signal of intensity 5×10−16W/m2 The maximum instantaneous potential difference across the two ends of the antenna is
- 1.23μV
- 1.23mV
- 1.23V
- 12.3mV
Q. To double the covering range of a T.V. transmitter tower, its height should be made:
- 4 times
- 2 times
- √2 times
- 8 times
Q. To cover population of 20 lakh, a transmission tower should have a height of:
(Radius of the earth = 6, 400km, Population is 1000/km2 )
- 25 m
- 50 m
- 75 m
- 100 m
Q. A tank with vertical walls is mounted so that its base is at a height of 1.2m above the horizontal ground. The tank is filled with water to a depth 2.8m. A hole is punched in the side wall of thetank at a depth x m below the surface of water to have maximum range of the emerging stream.Then the value of x in meter is
- 4.0
- 1.6
- 2.0
- 2.3