Dipoles
Trending Questions
Q. Three point charges +q, −2q and +q are placed at (x=0, y=a, z=0), (x=0, y=0, z=0) and (x=a, y=0, z=0) respectively. The magnitude and direction of the electric dipole moment vector for the given system of charges are
- √2 qa along +x direction
- √2 qa along +y direction
- √2 qa along the line joining points (x=0, y=0, z=0) and (x=a, y=a, z=0)
- qa along the line joining points (x=a, y=0, z=0) and (x=a, y=a, z=0)
Q. Three particles, each of mass m and carrying a charge q are suspended from a common point by insulating massless strings, each of length L. If the particles are in equilibrium and are located at the corners of an equilateral triangle of side a, then calculate the charge q on each particle.
[Assume L>>a].
[Assume L>>a].
- [4πϵ0a3mg3L]13
- [4πϵ0a3mg3L]12
- [2πϵ0a3mg3L]12
- None
Q. Which of the following graph of electrostatic force between two positive charges (Fe) vs r2, is a correct representation?
(r is the distance between two charges)
(r is the distance between two charges)
Q. A semi circular ring of radius R as shown in figure has charge per unit length λ=λ0cos θ. Electric dipole moment of this ring is.
- λR2
- 2λR2
- λR22
- 32λR2
Q. A point negative charge −Q is placed at a distance r from a dipole with dipole moment P in the x-y plane as shown in figure
The x-component of force acting on the charge −Q is
The x-component of force acting on the charge −Q is
−PkQrcosθ^i
PkQrcosθ^i
−2PkQr3cosθ^i
- 2PkQr3cosθ ^i
Q. Charges −q and +q located at A and B respectively, constitute an electric dipole. Distance AB=2a, O is the mid point of the dipole and OP is perpendicular to AB. A charge Q is placed at P where OP=y and y>>2a. The charge Q experiences an electrostatic force F. If Q is now moved along the equatorial line to P′ such that OP′=(y3), the force on Q will be close to
Here (y3>>2a)
Here (y3>>2a)
- 3F
- F3
- 9F
- 27F
Q. The magnitude of electric field intensity at point P (2, 0, 0) due to a dipole of dipole moment, →p=^i+√3^j kept at origin is -
(Assume that the point P is at large distance from the dipole and K=14πϵ0)
(Assume that the point P is at large distance from the dipole and K=14πϵ0)
- √7K4
- √7K8
- √13K4
- √15K4
Q. Two positive charges (+10 C) are kept on the arc of a circle and a negative charge (−20 C) at the origin (centre of circle). Find the magnitude of net dipole moment for the given system.
- 59.3 C-m
- 69.3 C-m
- 79.3 C-m
- 89.3 C-m
Q. A point charge Q is placed just outside a cube of side 'a' near corner H. Flux of electric field associated with face ABCD is
- 0
- Q4ε0
- Q24ε0
- Q8ε0
Q. A point dipole of dipole moment p is placed along y-axis, a point charge is placed at x-axis at distance r from point dipole, find net force on dipole due to point charge.
- 2kpr3q0^j
- kpr3q0^j
- kpr3q0^j
- zero because total charge on dipole is zero.
Q. Three charges are arranged on the vertices of an equilateral triangle as shown in figure. Find the magnitude of dipole moment of the combination.
- √2qd
- √3qd
- √5qd
- √6qd
Q. Two infinitely long static line charge of constant positive line charge density λ are kept parallel to each other. If a point charge +q is kept in equilibrium between them and is given small displacement along x− axis about its equilibrium position then the correct statement is
[Charge +q is confined to move in the x direction only]
[Charge +q is confined to move in the x direction only]
- Charge executes simple harmonic motion
- Charge contines to move in the direction of its displacement
- Charge takes circular path
- Charge takes parabolic path
Q. . A positively charged thin metal ring of radius R is fixed in x-y plane with its centre at the originA negatively charged particle P is released from rest at the point (0, 0, Z.). Then the motion of Pis(a) periodic for all values of Z, (b) SHM for all values of Z, satisfying 0 > R(d) None of the above
Q. Two pith balls carrying equal charges are suspended from a common point by strings of equal length, the equilibrium separation between them is r. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now becomes-
- (2r3)
- (r√2)2
- (r3√2)
- (2r√3)
Q. Find the electric field at the centre of a uniformly charged semicircular ring of radius R and linear charge density λ :
- λ2πε0R
- λπε0R
- 2λ2πε0R
- 0
Q. A thin Non-conducting rod is bent into a semicircle of radius r. A charge +Q is uniformly distributed along the upper half and a charge −Q is uniformly distributed along the lower half, as shown in figure. Find the electric field E at P.
- 4Qπ2ϵ0r2
- 2Qπ2ϵ0r2
- Q4π2ϵ0r2
- Qπ2ϵ0r2
Q. Statement I: Dipole is a scalar Quantity.
Statement II: Dipole is a vector Quantity.
Statement II: Dipole is a vector Quantity.
- Statement I – False
Statement II - True
- Statement I – True
Statement II - False
- Statement I – True
Statement II - True
- Statement I – False
Statement II - False
Q. The electric field at the centre of a uniformly charged ring is zero. What is the electric field at the centre of a half ring if the charge on it be Q and its radius be R?
- 14πε0QπR2
- 14πε0QR2
- 14πε02QπR2
- 14πε02QR2
Q. Electrostatic force F on a charge Q2 at an axial point due to a finite line charge varies as F=18000x2+4x, where x is in metres and is the distance along axial line from one of the ends. The total charge on the line is
- 2 C
- 0.02 C
- 0.002 C
- 0.004 C
Q. Three charges are arranged on the vertices of an equilateral triangle as shown in figure. Find the dipole moment of the combination.
Q. A thin semi-circular ring of radius r has a positive charge q distributed uniformly over it. The net electric field →E at the centre O is :
- q4π2ϵ0r2→j
- −q4π2ϵ0r2→j
- −q2π2ϵ0r2→j
- q2π2ϵ0r2→j
Q. In the given diagram, force acting on the conductor OA, aligned along the body digonal of the cube, is:
( Given, side of the cube is 2 m, I=2 A, →B=3^k T )
( Given, side of the cube is 2 m, I=2 A, →B=3^k T )
- 6 (^i+^j) N
- 3 (^i+^j) N
- (^i+^j) N
- 12 (^i+^j) N
Q. Three point charges +q, −2q and +q are placed at points (x=0, y=a, z=0), (x=0, y=0, z=0) and (x=a, y=0, z=0) respectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are:
- √2qa along +y direction
- √2qa along the line joining points (x=0, y=0, z=0) and (x=a, y=a, z=0)
- qa along the line joining points (x=0, y=0, z=0) and (x=a, y=a, z=0)
- √2qa along +x direction
Q. Three charges are arranged on the vertices of an equilateral triangle, as shown in the figure. Find the dipole moment of the combination.