Direction of Angular Velocity
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The boy running along a circular track of radius 7m and he completes one orbit in 10 seconds. find average speed and velocity.
- towards centre
- the tangent of the circular path
- away from centre
- the axis of rotation
- 0∘
- 45∘
- 180∘
- 360∘
The second’s hand of a clock is long. It goes round once every .
(a) What is the average speed of the tip of the second hand?
(b) What is the distance travelled by the tip in ?
(c) What is its average velocity during the time it makes one revolution? (Take )
- 45∘
- 180∘
- 360∘
- 0∘
- mω2l212
- mω2l224
- mω2l236
- mω2l248
- Ground
- 1.2 m below ground
- 1.6 m below ground
- 2 m above ground
The angle with the upward vertical, string makes where string becomes slack is
- θ=sin−1(−1√3)
- θ=cos−1(1√3)
- θ=cos−1(1√2)
- θ=sin−1(1√2)
- the tangent of the circular path
- towards centre
- away from centre
- the axis of rotation
- ^k
- −^j
- ^i
- −^k
A particle moves with constant angular velocity in a circle. During the motion its
Energy is conserved
Momentum is conserved
Energy and momentum both are conserved
None of the above is conserved
How are linear velocity and angular velocity related?
- (vbsin2θb)r
- (−vb)r
- (vbsinθb)r
- (vb)r
A person standing on the top of a cliff 171 ft high has to throw a packet to his friend standing on the ground 228 ft horizontally away. If he throws the packet directly aiming at the friend at the friend wuth a speed of 15.0 ft/s, how short will the packet fall ?
- →ω⊥→v
- →ω⊥→α
- →ω⊥→ac
- →v⊥→ac
If the angular velocity of a disc depends on an angle rotated as ω=(θ2+θ), then its angular acceleration at θ=1 rad is
- Constant in Magnitude
- Constant in magnitude as well as direction
- Constant in direction
- None of the above
- 255π
- 60π
- 1252π
- 120π
- Both magnitude and direction
- Neither magnitude nor direction
- Magnitude
- Direction
- Ground
- 1.6 m below ground
- 2 m above ground
- 1.2 m below ground
- the tangent of the circular path
- towards centre
- away from centre
- the axis of rotation
- Image B has to be rotated by 90 degrees anticlockwise to map with image A
- Image B should first have a mirror reflection and then be rotated to map with image A
- The width of image B should be reduced by 1 unit (1 square in the graph shown) and then rotated by 90 degrees to map with image A
- The width of image B should be increased by 1 unit (1 square in the graph shown) and then rotated by 90 degrees to map with image A
- Ground
- 1.6 m below ground
- 2 m above ground
- 1.2 m below ground
- tan−1(1)
- tan−1(4)
- tan−1(√3)
- tan−1(√2)