Electric Field Due to a Dipole Along the Equatorial Line
Trending Questions
Q.
The angle between the dipole moment and electric field at any point on the equatorial plane is
180∘
0∘
45∘
90∘
Q. The electric field at a point on equatorial line of a dipole and direction of the dipole moment
- Will be parallel
- Will be perpendicular
- Will be in opposite direction
- Are not related
Q. An electrical dipole of dipole moment ′p′ is placed in an electric field of intensity ′E′. The dipole acquires a position such that the axis of the dipole makes an angle θ with electric field. Assuming that the potential energy of the dipole to be zero when θ=90∘, the torque on dipole and the potential energy of the dipole will be respectively
- pEsinθ, 2pEcosθ
- pEcosθ, −pEsinθ
- pEsinθ, −pEcosθ
- pEsinθ, −2pEcosθ
Q.
Explain axial field or electric field at a point in end-on position, i.e. the axial position of an electric dipole.
Q. Two point dipoles p ^k and p2 ^k are located at (0, 0, 0) and (1 m, 0, 2 m) respectively. The resultant electric field due to the dipoles at the point (1 m, 0, 0) is xy×p4π ϵ0(−^k). The value of xy is .
Q. Two point charges +q and -q are held fixed at (-d, 0) and (d, 0) respectively of a (X, Y) coordinate system. Then
- E at all points on the Y-axis is along ^i
- Dipole moment is 2qd directed along ^i
- The electric field ˙E at all points on the X - axis has the same direction
- Work has to be done in bringing a test charge from infinity to the origin
Q. The electric field at a point on equatorial line of a dipole and direction of the dipole moment
- are parallel
- are opposite
- are perpendicular
- are not related
Q. A point charge +10 nC is located on the axis of a disc of radius 1 m at a distance of √3 m from the plane of the disc as shown in the figure. The electric flux from the charge passing through the disc is
(Take ϵo=9×10−12 C2/N-m2)
(Take ϵo=9×10−12 C2/N-m2)
- 64.4 N-m2/C
- 74.4 N-m2/C
- 84.4 N-m2/C
- 94.4 N-m2/C
Q. A charge 'q' is moved from a point A, above a dipole of dipole moment 'p', to a point B below the dipole in equatorial plane without acceleration. Find the work done in the process.
Q.
When a body is earthed, electrons flow from the earth into the body. This means the body is____________.
Q. A vertical rod of length l is moved with constant velocity v towards east. The vertical component of earth magnetic field is B and angle of dip is theta. The induced emf in the rod is 1 Blv sin theta 2 Blv tan theta 3 Blv cot theta 4 Blv cos theta
Q. An electric dipole is placed at the centre of a hollow sphere. The electric field intensity at a point outside the sphere at a distance x metres from the centre will be:
(charge of dipole is q and radius of sphere is R)
(charge of dipole is q and radius of sphere is R)
- kqx3
- kqxR3
- kqR2
- Zero
Q.
What is the angle between the electric dipole moment and the electric field on the equatorial line of the dipole?
Q. Derive an expression for electric field due electric dipole at a point on an equatorial line.
Q. A vertical rod of length l is moved with constant velocity v towards east. The vertical component of Earth magnetic field is B and angle of dip is theta. The induced e.m.f in the rod is?
Q.
A given point on the extension of an electric dipole has electric field =E if the dipole is suddenly turned by 90 degrees in clockwise direction electric field at the same point will be
Q. A very long magnet of pole strength 16 Am is placed vertically with its one pole on the table. At what distance from the pole, there will be a neutral point on the table
[Take BH=4×10−5 Wb m−2]
[Take BH=4×10−5 Wb m−2]
- 0.2 m
- 0.4 m
- 0.6 m
- 0.8 m
Q.
The electric field in a region is given by →E=(^3i−^4j) N/C. Find out the work done (in joule) in displacing a particle of charge 1C by 1 m along the line 4y = 3x + 9
Q.
Two charge of +25×10−9 C and −25×10−9 C
are placed 6 m apart. Find the electric field intensity ratio at point 4
m from the centre of the electric dipole
(i) on axial line
(ii) on equatorial line
Q. When a body is earth connected, electrons from the earth flow into the body. This means the body is
- uncharged.
- Charged positively.
- Charged negatively.
- an insulator.
Q. 53.The variation of electric field E, due to uniformly charged hollow sphere with distance r, from its centre? Why not option 4 correct?
Q. In a region of space, suppose there exists a uniform electric field →E=10^i V/m. If a positive charge +1 μC has been taken taken from a point A(1, 2) to B(1, 4). The work done by external force is:
- +40 V
- −20 V
- −40 V
- Zero
Q. Derive an expression for intensity of electric field at a point broadside position or an equatorial line of an electric dipole.
Q. Derive an expression for the electric field at a point on the equatorial plane of an electric dipole.
Q. The amount of work done in moving a point charge of 10C from the point A to B, as shown is
Spherical shell
Spherical shell
- 10 J
- 20 J
- zero
- 15 J
Q.
The angle between the electric dipole moment and the electric field strength due to it, on the equatorial line is :
- 1800
- 00
- 900
- 600
Q.
What is the angle between the electric dipole moment and the electric field on the equatorial line of the dipole?
0°
180°
none of these
90°
Q. Two point charges +q and -q are held fixed a (-d, 0) and (d, 0) respectively of a (X, Y) coordinate system. Then
- The electric field ˙E at all points on the X - axis has the same direction
- E at all points on the Y - axis is along ^i
- Dipole moment is 2qd directed along ^i
- Work has to be done in bringing a test charge from infinity to the origin
Q. alpha particle , beta particle and gamma rays each having emergy of 1MeV . which of these has highest penetrating power?? or all have equal penetrating power ?
Q. The magnitude fo earths magnetic field at a place is B0 and the angle of dip is δ. A horixontal conductor of length l lying magnetic north-south moves eastward with a velocity V. The emf induced across the conductor is
Options:
Zero
B0l V sin δ
B0l V cos δ
B0l V tan δ
