Electric Field Due to an Arc at the Centre
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Q.
A rod of length L has a total charge Q distributed uniformly along its length. It is bent in th shape of a semicircle. Find the magnitude of the electric field at the centre of curvatere of he semicircle.
Q. Figure shows a rod AB, which is bent in a 120∘ circular arc of radius R. A charge (−Q) is uniformly distributed over rod AB. What is the electric field →E at the centre of curvature O ?
- 3√3Q16π2ε0R2(ˆi)
- 3√3Q8π2ε0R2(ˆi)
- 3√3Q8πε0R2(ˆi)
- 3√3Q8π2ε0R2(−ˆi)
Q. The linear charge density of a uniform semicircular wire varies with θ as shown in the figure as λ=λ0cosθ. Find the charge on the wire if R is the radius of the ring.
- 3λ0R
- λ0R
- 2λ0R3
- 2λ0R
Q. For the given charge distribution on the ring, the net electric field at the centre of non-conducting ring is
(Assume the part of ring in first and third quadrant is neutral, second quadrant is positively charged, fourth quadrant is negatively charged)
(Assume the part of ring in first and third quadrant is neutral, second quadrant is positively charged, fourth quadrant is negatively charged)
- 180√2 N/C
- 180√3 N/C
- 180√5 N/C
- 180√7 N/C
Q.
If a long hollow copper pipe carries a direct current, the magnetic field associated with the current will be
Q. A thin Non-conducting rod is bent into a semicircle of radius r. A charge +Q is uniformly distributed along the upper half and a charge −Q is uniformly distributed along the lower half, as shown in figure. Find the electric field E at P.
- Qπ2ϵ0r2
- 2Qπ2ϵ0r2
- 4Qπ2ϵ0r2
- Q4π2ϵ0r2
Q. A 10 cm long rod carries a charge of +50μC distributed uniformly along its length. Find the magnitude of the electric field at a point 10 cm from both the ends of the rod.
- 4.2×107 N/C
- 5.2×107 N/C
- 6.2×107 N/C
- 7.2×107 N/C
Q. To get the formula of electric field due to a ring at the centre from the formula of electric field due to an arc at centre, replace θ with .
- 90∘
- 180∘
- 45∘
- 360∘
Q.
A magnetic wire of dipole moment is bent in the form of a semi-circle. What is the new magnetic moment is?
Q. A thin glass rod is bent into a semicircle of radius r. A charge +Q is uniformly distributed along the upper half and a charge –Q is uniformly distributed along the lower half, as shown in the figure. The electric field E at, P (the centre of the semicircle, is)
- Qπ2ε0r2
- 2Qπ2ε0r2
- 4Qπ2ε0r2
- Q4π2ε0r2
Q. A charge q is uniformly distributed on a spherical shell of radius R. The electric field at a distance 4R3 from the centre will be
- 9q64πε0R2
- q4πε0R3
- 3q16πε0R2
- Zero
Q. If O is the center of a ring of radius r, then find the potential at point O due to half ring that has a linear charge density λ.
- λ4ϵ0
- λ4π2ϵ0r
- λ4πϵ0r
- λ4πϵ0r2
Q. The linear charge density on a ring which varies with angle θ can be represented as λ=Kcosθ2, wherek = 2 cm^{-1}and\theta$ is the angle subtended by the radius of the ring with the horizontal. The potential at the centre of the ring is
Q. Charge q is uniformly distributed over a thin half ring of radius R. The electric field at the centre of the ring is
- q2π2ϵ0R2
- q4π2ϵ0R2
- q4πϵ0R2
- q2πϵ0R2
Q. For the given semi-infinite rod of uniformly distributed line charge, angle (θ) between net electric field and component of net electric field perpendicular to the axis of line charge at the point P is
- 30∘
- 45∘
- 60∘
- 15∘
Q. A large plane charged sheet having surface charge density σ=+2×10−6 C/m2 lies in the x-y plane. Find the flux of the electric field through a circular area of radius 1 cm lying completely in the region where x, y, z all are positive and with its normal making an angle of 60∘ with the z-axis.
- 16.3 Nm2/C
- 17.3 Nm2/C
- 8.15 Nm2/C
- 34.6 Nm2/C
Q. For the given uniformly charged ring sector symmetrically placed about Y axis, net electric filed at the point P along X-direction is
[l is the length of the arc, λ is linear charge density, R is radius of sector]
[l is the length of the arc, λ is linear charge density, R is radius of sector]
- 2kλRsin(l2R)
- 2kλRsin(lR)
- 2kλR
- Zero
Q. For the given charge distribution, the net electric field at the centre of the non-conducting ring is
- 180 N/C
- 220 N/C
- 320 N/C
- 360 N/C
Q. For the given uniformly charged ring of linear charge density +10 nC/m, the electric field in y− direction at point P is
- 100 N/C
- 200 N/C
- Zero
- 150 N/C
Q. Two mutually perpendicular infinite wires carry positive charge densities λ1 and λ2. The electric lines of force makes angle α with second wire then λ1λ2 is
- tan2α
- cot2α
- sin2α
- cos2α
Q. An insulating rod of length l carries a charge q uniformly distributed on it. The rod is pivoted at one of its ends, and it is rotated at a frequency f about a fixed perpendicular axis in the horizontal plane. The magnetic moment of the rod is
- πqfl212
- πqfl22
- πqfl26
- πqfl23
Q. A 10 cm long rod carries a charge of +50μC distributed uniformly along its length. Find the magnitude of the electric field at a point 10 cm from both the ends of the rod.
- 4.2×107 N/C
- 5.2×107 N/C
- 6.2×107 N/C
- 7.2×107 N/C
Q.
A circular arc has a radius of 0.1m. The angle it subtends at the Centreis π6 . If the charge it carries is 10C. what is the linear charge density of the wire?
192.3 c/m
215.2 c/m
50 c/m
500 c/m
Q. A large charged conducting sheet is placed in a uniform electric field, perpendicularly to the electric field lines. After placing the sheet into the field, the electric field on the left side of the sheet is E1=5×105 V/m and on the right it is E2=3×105 V/m. The sheet experiences a net electric force of 0.08 N. Find the area of one face of the sheet.( Assume the external field to remain constant after introducing the large sheet)
[k=14πε0=9×109 Nm2C−2]
[k=14πε0=9×109 Nm2C−2]
- 3.6π×10−2 m2
- 0.9π×10−2 m2
- 1.8π×10−2 m2
- None
Q. Find the magnitude of the electric field (|−−→Eind|) at the center of the sphere due to the induced charges on the sphere.
- Kq2
- Kq8
- Kq5
- Kq4
Q. Charge Q is distributed uniformly on length l of a wire. It is bent in the form of a semicircular ring. Find the electric field at the centre of the ring.
- Q2πε0l2
- Q4πε0l2
- Qπ4ε0l2
- Q2ε0l2
Q. The magnitude of electric field E in the annular region of a charged cylindrical capacitor
- is the same throughout.
- is higher near the outer cylinder than near to it.
- varies as 1r, where r is the distance from the axis.
- varies as 1r2, where r is the distance from the axis.
Q. For the given charge distribution on the ring, the net electric field at the centre of non-conducting ring is
(Assume the part of ring in first and third quadrant is neutral, second quadrant is positively charged, fourth quadrant is negatively charged)
(Assume the part of ring in first and third quadrant is neutral, second quadrant is positively charged, fourth quadrant is negatively charged)
- 180√2 N/C
- 180√3 N/C
- 180√5 N/C
- 180√7 N/C
Q. A long straight conductor, carrying a current i, is bent to form an almost complete circular loop of radius r as shown. The magnetic field at the centre of the loop :
- has magnitude μ0ir(1−1π)
- has magnitude μ0ir(1+1π)
- has magnitude μ0i2r(1−1π)
- has magnitude μ0i2r(1+1π)
Q. A thin glass rod is bent into a semicircular shape of radius R. A charge +Q is uniformly distributed along the upper half and a charge −Q is distributed uniformly along the lower half as shown. The electric field at the centre P is:
- √2Q4πε0R2
- Q√2πε0R2
- Q2πε0R2
- Qπ2ε0R2