Electric Potential Due to Shell
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Q. A spherical conductor of radius 2m is charged to a potential of 120 V. It is now placed inside another hollow spherical conductor of radius 6m. Calculate the potential to which the bigger sphere would be raised to?
- 20 V
- 60 V
- 40 V
- 80 V
Q. If the electric potential of the inner shell is 20 V and that of the outer shell is 10 V, then the potential at the centre will be (in V):
[Assume both thin shells to be conducting]

[Assume both thin shells to be conducting]

Q. A hollow conducting sphere of radius R has a charge (+Q) on its surface. What is the electric potential within the sphere at a distance r=R3 from its centre
- Zero
- 14πϵ0QR
- 14πϵ0Qr
- 14πϵ0Qr2
Q. If on the concentric hollow spheres of radii r and R(>r) the charge Q is distributed such that their surface densities are same then the potential at their common centre is
- Zero
- Q(R2+r2)4πϵ0(R+r)
- QRR+r
- Q(R+r)4πϵ0(R2+r2)
Q. A hollow metal sphere of radius 5 cm is charged such that the potential on its surface is 10 volt. The potential at the centre of the sphere is
(IIT-JEE 1983)
(IIT-JEE 1983)
- zero
- same as at a point 5 cm away from the surface
- 10 volt
- same as at a point 25 cm away from the surface
Q. The amount of work done in moving a point charge of 10C from the point A to B, as shown is

Spherical shell

Spherical shell
- 10 J
- 15 J
- 20 J
- zero
Q. Two insulated charged conducting spheres of radii 20 cm and 15 cm respectively and having an equal charge of 10 C are connected by a copper wire and then they are separated. Then
- Surface charge density on the 15 cm sphere will be greater than that on the 20 cm sphere
- Both the spheres will have the same charge of 10 C
- Surface charge density on the 20 cm sphere will be greater than that on the 15 cm sphere
- Surface charge density on the two spheres will be equal
Q. If a charge Q is distributed on the concentric hollow spheres of radii r and R(> r) such that their surface densities are equal then the potential at their common centre is
- Zero
- Q(R2+r2)4πϵ0(R+r)
- QRR+r
- Q(R+r)4πϵ0(R2+r2)
Q. Two conducting spheres of radii a and b respectively are charged and joined by a wire. The ratio of electric field due the spheres at their surfaces when isolated is
- ba
- a2b2
- ab
- b2a2
Q. Equal charges are given to two conducting spheres of different radii. The potential will be
- more on the smaller sphere
- more on the bigger sphere
- equal on both the spheres
- Dependent on the nature of the materials of the spheres