Equilibrium and Its Types
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Q. Potential energy of a system of particles is U=α3r3−β2r2, where r is distance between the particles. Here α and β are positive constants. Which of the following are correct for the system?
- Equilibrium separation between the particles is αβ
- For r=αβ, the equilibrium is stable
- For r=αβ, the equilibrium is unstable
- Work required to slowly move the particles to infinite separation from initial equilibrium position is βα
Q. The potential energy function for the force between two atoms in a diatomic molecule is approximately given by U(x)=ax12−bx6, where a and b are constants and x is the distance between the atoms. If the dissociation energy of the molecule is D=[Ux=∞−Uat equilibrium], D is
- b22a
- b212a
- b24a
- b26a
Q. The potential energy of a particle is given by, U=2x3−3x2. (in SI unit) The nature of equilibrium at x=0 & x=1 are
- Stable, Unstable
- Unstable, Stable
- Neutral, Unstable
- Unstable, Neutral
Q. The potential energy between two atoms in a molecule is given by U(x)=ax12−bx6 where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibrium when
- x=(2ab)16
- x=(11a5b)16
- x=0
- x=(a2b)16
Q. The graph of potential energy (U) Vs position (X) is shown in the figure given below. Select the correct order regarding the equilibrium state of (a), (b) & (c).
- Stable, Unstable, Neutral
- Unstable, Stable, Neutral
- Neutral, Stable, Unstable
- Neutral, Unstable, Stable
Q. The potential energy between two atoms in a molecule is given by U=ax3−bx2 where a and b are positive constants and x is the distance between the atoms. The atom is in stable equilibrium when x is equal to
- 0
- 2b3a
- 3a2b
- 3b2a
Q. Potential energy of a particle moving along x− axis is given by U=(x33−4x+6).
Here, U is in joules and x in metres. Find the position of stable and unstable equilibriums, respectively.
Here, U is in joules and x in metres. Find the position of stable and unstable equilibriums, respectively.
- x=2 m and x=−2 m
- x=−2 m and x=2 m
- x=0 and x=0
- x=1 m and x=−1 m
Q. Two billiard balls A and B, each of mass 50g and moving in opposite directions with speed of 5m/s each, collide and rebound with the same speed. If the collision lasts for 10–3s, which of the following statements are true?
- The impulse imparted to each ball is 0.25kgm/s and the force on each ball is 250N.
- The impulse and the force on each ball are equal in magnitude and opposite in direction.
- The impulse imparted to each ball is 0.25kgm/s and the force exerted on each ball is 25×10–5N.
- The impulse imparted to each ball is 0.5Ns.
Q. The potential energy of a particle moving along x−axis, under the action of conservative force, is given by U=20+5sin(4πx), where U is in Joules and x is in metres. Then which of the following is/are true?
- at x=78 m, particle is at equilibrium
- at x=78 m, particle is not at equilibrium.
- at x=38 m, particle is at equilibrium.
- at x=38 m, particle is not at equilibrium.
Q. The potential energy function for the force between two atoms in a diatomic molecule which is approximately given as,
U(x)=ax12−bx6. Where a & b are constants and x is the distance between the atoms. The disassociation energy of the molecule, D=[U(x=∞)−Uequilibrium] is
U(x)=ax12−bx6. Where a & b are constants and x is the distance between the atoms. The disassociation energy of the molecule, D=[U(x=∞)−Uequilibrium] is
- b22a
- b212a
- b24a
- b26a
Q. Figure shows two identical particles 1 and 2, each of mass m, moving in opposite directions with same speed v along parallel lines. At a particular instant, →r1 and →r2 are their respective position vectors drawn from point A which is in the plane of the parallel lines.
Choose the correct options:
Choose the correct options:
- Total angular momentum of the system about A is
→l=|mv(→r1+→r2)|⨀ - Total angular momentum of the system about A is
→l=mv(d2−d1)⨂ - Angular momentum →l2 of particle 2 about A is →l2=mvr2⨀
- Angular momentum →l1 of particle 1 about A is →l1=mv(d1)⨀
Q. A conservative force →F is acting on a particle and the particle moves from Point C to D and then from D to C. The work done by the force is
- W = 0
- W > 0
- W≠0
- W < 0
Q. An object, initially at rest, explodes in three fragments. The momentum of two pieces is \(-3p\hat{i}\) and \(-4p\hat{j}\) where \(p\) is a positive number. The momentum of the third piece
\((i)\) will have magnitude \(5p\)
\((ii)\) will make an angle \(\tan^{-1}(4/3)\) with the \(x\)-axis
\((iii)\) will make an angle \(\tan^{-1}(3/4)\) with the \(x\)-axis
\((iv)\) will have magnitude \(7p\).
\((i)\) will have magnitude \(5p\)
\((ii)\) will make an angle \(\tan^{-1}(4/3)\) with the \(x\)-axis
\((iii)\) will make an angle \(\tan^{-1}(3/4)\) with the \(x\)-axis
\((iv)\) will have magnitude \(7p\).
Q. The potential energy of a particle is given by relation U=x3−6x2 (In SI units). The nature of equilibrium at x=0 is
- Stable
- Unstable
- Neutral
- Undefined
Q. The potential energy of a particle varies with distance x as shown in the graph.
The force acting on the particle is zero at
The force acting on the particle is zero at
- C
- B
- A and D
- B and C
Q. The potential energy of a particle in a force field is given by the equation E=x33−4x2+15x−6 Choose the correct statement among the options.
- no points of equilibrium exist.
- x=3 and x=5 are points of equilibrium.
- There is a stable equilibrium at x=3 and unstable equilibrium at x=5.
- There is neutral equilibrium at x=3 and x=5.