Extended Object Image Formation
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One end of a horizontal cylindrical glass rod (μ=1.5) of radius 5.0 cm is rounded in the shape of a hemisphere. An object 0.5 mm high is placed perpendicular to the axis of the rod at a distance of 20.0 cm from the rounded edge. Locate the image of the object and find its height.
Same height as that of object & erect.
Same height as that of object & inverted.
Double the height of the object & inverted.
Half the height of the object & inverted.
For the spherical interface shown in the figure, the two different media with refractive indicesand are present as shown. The image will be formed at
One end of a horizontal cylindrical glass rod (μ=1.5) of radius 5.0 cm is rounded in the shape of a hemisphere. An object 0.5 mm high is placed perpendicular to the axis of the rod at a distance of 20.0 cm from the rounded edge. Locate the image of the object and find its height.
Same height as that of object & erect.
Same height as that of object & inverted.
Double the height of the object & inverted.
Half the height of the object & inverted.
- 17 cm, left of S4
- 25 cm, right of S4
- 13 cm, left of S4
- 10 cm, left of S4
For which value of x, of the following, will the final image of the object at O be virtual?
- 2R
- R/2
- 3R
- 1.5R
- 6m
- 30cm
- 5cm
- 3m
- 30∘
- 90∘
- 60∘
- 45∘
One end of a horizontal cylindrical glass rod (μ=1.5) of radius 5.0 cm is rounded in the shape of a hemisphere. An object 0.5 mm high is placed perpendicular to the axis of the rod at a distance of 20.0 cm from the rounded edge. Locate the image of the object and find its height.
Same height as that of object & erect.
Same height as that of object & inverted.
Double the height of the object & inverted.
Half the height of the object & inverted.