General Gravity Problem
Trending Questions
A player throws a ball upwards with an initial speed of 29.4 ms−1.
(a) What is the direction of acceleration during the upward motion of the ball?
(b) What are the velocity and acceleration of the ball at the highest point of its motion?
(c) Choose the x = 0 m and t = 0 s to be the location and time of the ball at its highest point, vertically downward direction to be the positive direction of x-axis, and give the signs of position, velocity and acceleration of the ball during its upward, and downward motion.
(d) To what height does the ball rise and after how long does the ball return to the player’s hands? (Take g = 9.8 ms−2 and neglect air resistance).
A stone is thrown vertically upward with an initial velocity of Taking , find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone when the stone returns to ground?
A ball is thrown vertically upwards from the top of a tower at 4.9 m/s. It strikes the pond near the base of the tower after 3 seconds. The height of the tower is
- 73.5 m
- None of these
- 44.1 m
- 29.4 m
- 19.6 m
- 9.8 m
- 24.5 m
- 14.7 m
- 3 s
- 4 s
- 5 s
- 2 s
- 91 m
- 293 m
- 111 m
- 182 m
A parachutist drops first freely from an aeroplane for 10s and then parachute opens out. Now he descends with a net retardation of 2.5 m/ s2. If he falls out of the plane at a height of 2495 m and g=10 m/s2, his velocity on reaching the ground will be
10 m/s
15 m/s
5 m/s
20 m/s
To test the quality of a tennis ball, you drop it onto the floor from a height of 4.00 m. It rebounds to a height of 2.00 m. If the ball is in contact with the floor for 12.0ms, then what is the average acceleration during that contact?
- 1.26 × 103 m/s2
+ 10 m/s2
- 10 m/s2
+ 1.26 × 103 m/s2
- 293 m
- 182 m
- 111 m
- 91 m
A balloon is at a height of 81 m and is ascending upwards with a velocity of 12ms. A body of 2kg weight is dropped from it. If g=10ms2, the body will reach the surface of the earth in
A. 4.025 s
B. 5.4 s
C. 6.75 s
D. 1.5 s
a body slides down from rest from the top of 6.4m long rough plane inclined at 30degree with the horizontal find the time taken by block in reaching the bottom of the plane Take coefficient of friction to be 0.2 and g=9.8m/s^2
- 980 m
- 735 m
- 245 m
- 490 m
- 150 m
- 100 m
- 200 m
- 400 m
- t=t1−t2
- t=t1+t22
- t=√t1t2
- t=t21t22
- Dr. A. P. J. Abdul Kalam
- Dr. C .V. Raman
- Dr. Har Gobind Khorana
- None of the above
- u22(g+a)
- u2(g+a)
- u2(g+a)
- u(g+a)
- t = t1 - t2
A ball is thrown up from the top of a tower at 20 m/s velocity. It took the ball 6 sec to fall to the bottom. For how long was the ball above the tower?
2 sec
4 sec
6 sec
1 sec
- 100 meters
- 320 meters
- 80 meters
- 240 meters
- 4.9m
- 9.8m
- 12.4m
- 19.6m
- 2m
- 3.33m
- 4m
- (4/3)m
- 75 m/s
- 94 m/s
- 64 m/s
- 84 m/s
- 14.7 m
- 19.6 m
- 9.8 m
- 24.5 m
- 12.25 m/s
- 14.75 m/s
- 16.23 m/s
- 17.15 m/s
A body A is projected upwards with a velocity of 98 m/s. The second body B is projected upwards with the same initial velocity but after 4 sec. Both the bodies will meet after
6 sec
8 sec
10 sec
12 sec