Gravitational Potential of a Solid Sphere
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Q. From a solid sphere of mass M and radius R, a spherical portion of radius R2 is removed, as shown in the figure. Taking gravitational potential V=0 at r=∞ , the potential at the centre of the cavity thus formed is
(G= gravitational constant)
(G= gravitational constant)
- −GM2R
- −GMR
- −2GM3R
- −2GMR
Q. How to find gravitational potential at a centre of the earth, at the surface of the earth is zero
Q.
A ball is allowed to fall from a height of 10m. If there is 40% loss of energy due to impact then after one impact ball will go up by??
Q.
In a gravitational field, at a point where the gravitational potential is zero
The gravitational field is necessarily zero
The gravitational field is not necessarily zero
Nothing can be said definitely about the gravitational field
None of these
Q. A particle of mass M is placed at the centre of a uniform spherical shell of equal mass and radius a. Find the gravitational potential at a point P at a distance a/2 from the centre.
- −3GMa
- −5GMa
- −5GM2a
- −2GM3a
Q. A mass of 50 kg is placed at the center of a uniform spherical shell of mass 100 kg and radius 50 m. If the gravitational potential at a point, 25 m from the center is V kg/m. The value of V is:
Q. Inside a fixed sphere of radius R and uniform desnity ρ, there is a sphericfal cavity of radius R/2 such that the surface of cavity passes through the center of the sphere as shown in the figure. A particle of mass m0 is released from rest from centre B of cavity which strikes the center A of sphere with a velocity which is equal to √2πGρR2√β. Then the value of β will be .
Q.
In a hollow spherical shell, potential (V) changes with respect to distance (r) from centre as