Intro to Projectile on an Incline
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A body is projected atwith a velocity at an angle of with the horizontal. The radius of curvature of its trajectory at is . Neglecting air resistance and taking acceleration due to gravity, the value of is :
- V0=√gH5
- V0=√gH7
- V0=√2gH5
- V0=√2gH7
A particle is projected from a point on the surface of smooth inclined plane (see figure). Simultaneously another particle Q is released on the smooth inclined plane from the same position. P and Q collide on the inclined plane after t= 4 second. The speed of projection of P is
- cotβ2
- cosec β
- tanβ2
- sinβ2
- If the particle strikes the plane at right angles, then tanα=cotβ+2tanβ
- If the particle strikes the plane horizontally, then tanα=2tanβ
- If the particle strikes the plane at right angles, then tanβ=cotβ+2tanα
- If the particle strikes the plane horizontally, then tanβ=2tanα
A body thrown up along a frictionless inclined plane of angle of inclination 30∘ covers a distance of 40 m along the plane. If the body id projected with the same speed at an angle of 30∘ with the ground, it will have a range of
(Take g=10 ms−2)
20 m
40 m
20√2 m
20√3 m
- 500 m
- 10003 m
- 200√2 m
- 100 m
- 60 m
- 71 m
- 100 m
- 141 m
- α=30∘+tan−12√3
- 45∘
- 60∘
- α=30∘+tan−1√32
- ucos(α−β)
- usin(α−β)
- usin(α2)
- ucos(β2)
- 2u2sin(α−β)cosαgcos2β
- 2u2sin(α+β)cosαgcos2β
- u2sin(α−β)cosαgcos2β
- u2sin(α+β)cosαgcos2β
- V0=√2gH5
- V0=√2gH7
- V0=√gH5
- V0=√gH7
- 25m
- 37m
- 50m
- 100m
- 300+tan−1(√32)
- 600
- 300+tan−1(2√3)
- 450
A body is projected up a smooth inclined plane (length = 20√2m ) with velocity u from the point M as shown in the figure. The angle of inclination is 45∘ and the top is connected to a well of diameter 40 m. If the body just manages to cross the well, what is the value of v
40 ms−1
40 √2 ms−1
20 ms−1
20 √2 ms−1
a. tanα+cotβ+2tanβ, if the particle strikes the plane at right angles
b. tanα=2tanβ if the particle strikes the plane horizontally.
- tan−1(3)
- tan−1(2)
- tan−1(√2)
- tan−1(4)
- (xr0)2+a(yv0)2=1
- (xr0)2+a(yv0)2=0
- (xr0)2+(yv0)2=1α
- noneofthese
- a2
- a
- 2a
- None of these
- 2r
- r(√2−1)
- r√2
- r(√2−1)
- 5π36rad
- 11π36rad
- 7π36rad
- 13π36rad
- 5π36 radian
- 13π36 radian
- 11π36 radian
- 7π36 radian
- 377m
- 36m
- 16m
- 4m
A particle is projected at an angle of 37∘ with an inclined plane. The inclined plane is at an angle of 60∘ with the horizontal. Find
I. Time of flight of particle.
II. Distance traveled by particle (AB) along the inclined plane
I. Time of flight =1.2s
II. Distance traveled =5.7mI. Time of flight =2.4s
II. Distance traveled =5.7mI. Time of flight =4.8s
II. Distance traveled =11.4mI. Time of flight =6.4s
II. Distance traveled =11.4m