KE & PE Graph
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Q.
is the time – displacement equation of an SHM, At t = 0, the displacement of the particle is and it is moving along negative x-direction. Then, the initial phase angle will be.
Q. The displacement time graph of a particle executing S.H.M. is given in figure : (sketch is schematic and not to scale)
Which of the following statements is/are true for this motion?
(a)The force is zero at t=3T4
(b)The acceleration is maximum at t=T
(c)The speed is maximum at t=T4
(d)The P.E. is equal to K.E. of the oscillation at t=T2
Which of the following statements is/are true for this motion?
(a)The force is zero at t=3T4
(b)The acceleration is maximum at t=T
(c)The speed is maximum at t=T4
(d)The P.E. is equal to K.E. of the oscillation at t=T2
- (a), (b) and (d)
- (b), (c) and (d)
- (a), (b) and (c)
- (a) and (d)
Q. Two simple harmonic motion, are represented by the equations y1=10sin(3πt+π3)
y2=5(sin3πt+√3cos3πt)
Ratio of amplitude of
y1 to y2=x:1.
The value of x is _________.
y2=5(sin3πt+√3cos3πt)
Ratio of amplitude of
y1 to y2=x:1.
The value of x is _________.
Q. For a particle executing S.H.M. the displacement x is given by x=Acosωt. Identify the graph which represents the variation of potential energy (P.E.) as a function of time t and displacement x.
- II, IV
- II, III
- I, III
- I, IV
Q. A particle of mass m is placed in one-dimensional potential field where potential energy varies as U(x)=U0 (1−cosbx) where U0 and b are constants. The period of small amplitude oscillation of the particle is
Q. The ratio of maximum and minimum intensities of two sources is 4:1. The ratio of their amplitudes is-
- 1:3
- 3:1
- 1:9
- 1:1
Q. A body executes simple harmonic motion. The potential energy (PE), the kinetic energy (KE) and total energy (TE) are measured as a function of displacement (x). Which of the following statements is true?
- PE is maximum when x=0
- KE is maximum when x=0
- TE is zero when x=0
- KE is maximum when x is maximum
Q. A simple harmonic motion is given by the equation
x=3 sin 3 πt+4 cos 3 πt
where x is in metres. The amplitude of the motion is
x=3 sin 3 πt+4 cos 3 πt
where x is in metres. The amplitude of the motion is
- 3 m
- 4 m
- 5 m
- 7 m
Q. The period of a particle in SHM is 8 s. At t=0, it is at the mean position. The ratio of the distance travelled by it in the 1st and the 2nd second is
- 12
- 1√2
- √2
- √2+1
Q.
If one joule of energy is converted to a new system of units in which length is measured in 10m, mass in 10 kilogram and time in 1 minute.What is the value of energy in this new system.
Q.
What is the maximum extension in the spring shown in figure?
None