Magnitude and Direction of Acceleration
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- 1.2 m
- 4.0 m
- 6 m
- 3.2 m
- 1 m/s2
- 2 m/s2
- √2 m/s2
- √5 m/s2
- Particle accelerates for 0≤t<2
- Particle accelerates for 2≤t≤4
- Maximum speed attained by the body between 0 to 4 sec is 4 m/s
- Particle retards for 2<t≤4
- Circle
- parabola
- Ellipse
- Straight line
- 9x=24y+y2
- 18x=24y+5y2
- 18x=12y+10y2
- 36x=24y−5y2
- uniform velocity.
- varying speed.
- uniform acceleration.
- uniform speed and acceleration of fixed magnitude.
- a=bcosαcosβ
- a=bcosβcosα
- a=bcos2βsinα
- a=bsin2βcosα
So in 2D motion does the instantaneous acceleration always have to be along the same line as velocity( either 0 or 180 degrees)?
In 2D acceleration will not be a vector
Yes, It has to be either at 0 or 180 degree to the velocity
It can also be perpendicular to velocity but not any other angle
It can point in any arbitrary direction
A particle is moving along the curve . If , then the particle would be moving with uniform
Rotation
Velocity
Acceleration
Retardation
- 320 m
- 160 m
- 480 m
- 720 m
A 1.0 m long metallic rod is rotated with an angular frequency of 400 rad s−1 about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field of 0.5 T parallel to the axis exists everywhere. Calculate the emf developed between the centre and the ring.