Moment of Inertia of a Rod
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cusec is equal to how many litres?
A ring is hung on a nail. It can oscillate, without slipping or sliding
In its plane with a time period and,
Back and forth in a direction perpendicular to its plane, with a period.
The ratio will be:
The moment of inertia of a square lamina about the perpendicular axis through its center of mass is 20 kg per meter square then its moment of inertia about an axis touching its side and in the plane of the lamina will be
Find the center of mass of uniform semicircular ring of radius and mass
- Ml23
- Ml212
- 10Ml23
- Ml224
- ml2
- 3ml24
- ml22
- ml24
- 3π2
- 2π2
- π22
- π23
[Take permissible stress for fillet weld = 108 MPa]
- 70
- 104
- 128
- 15
A ring of mass M and radius R is rotating with angular speed about a fixed vertical axis passing through its centre O with two point masses each of mass M8 at rest at O. These masses can move radially outwards along two massless rods fixed on the ring as shown in the figure. At some instant the angular speed of system is 89ω and one of the masses is at a distance of 35R from O. At this instant the distance of the other mass from O is
23R
13R
35R
45R
- ml212
- ml23
- ml26
- ml24
- πfQl2
- πfQl23
- 2πfQl23
- 2πfQl2
- L2
- L√2
- √2L
- 2L
- gsinθ
- gLsinθ
- 3g2Lsinθ
- 6gLsinθ
- Ml23
- Ml26
- none of these
- Ml24
- ml212
- ml23
- 2ml23
- ml26
Calculate the torque on the square plate of the previous problem if it rotates about a diagonal with the same angular acceleration.
- Ix=Iy>Iz
- Ix>Iy>Iz
- Iz>Iy>Ix
- Ix=Iy<Iz
- 5000 Am2
- 3300 Am2
- 490 Am2
- 350 Am2
- 120 kg-m2
- 30 kg-m2
- 60 kg-m2
- 360 kg-m2
A man sitting in a train in motion is facing the engine. He tosses a coin up, the coin falls behind him. The train is moving:
forward with uniform speed
backward with uniform speed
forward with acceleration
forward with retardation
Which of the following relations is wrong?
Torque = Moment of inertia × Angular acceleration
Torque = Magnetic moment × Magnetic field
Moment of inertia = Torque × Angular acceleration
Linear momentum = Moment of inertia × Angular velocity
Water leaks out from an open tank through a hole of area 2 mm2 in the bottom. Suppose water is filled up to a height of 80 cm and the area of cross section of the tank is 0.4 m2. The pressure at the open surface and at the hole are equal to the atmospheric pressure. Neglect the small velocity of the water near the open surface in the tank. (a) Find the initial speed of water coming out of the hole. (b) Find the speed of water coming out when half of water has leaked out. (c) Find the volume of water leaked out during a time interval dt after the height remained is h. Thus find the decrease in height dh in terms of h and dt. (d) From the result of part (c) find the time required for half of the water to leak out.
A ball of radius has a round hole of radius drilled through its center. find the volume of the resulting solid.
- π4nρl3
- nρl3
- π3nρl3
- πnρl3
- Both rods elongate by the same amount
- Mild steel rod elongates more than the cast iron
- Cast iron rod elongates more than the mild steel rod
- As the stresses are equal strains are also equal in both the rods
- 43.2 kg-m2
- 24 kg-m2
- 12 kg-m2
- 38 kg-m2