Partially Filled Dielectrics
Trending Questions
Q. The capacitance of a parallel plate capacitor with air as medium is 6 μF. With the introduction of a dielectric medium, the capacitance becomes 30 μF. The permittivity of the medium is: ε0=8.85×10−12 C2N−1m−2
- 0.44×10−10 C2N−1m−2
- 5.00 C2N−1m−2
- 0.44×10−13 C2N−1m−2
- 1.77×10−12 C2N−1m−2
Q. An electric dipole consisting of two equal and opposite point charges (q, m) and dipole length=2l is slightly disturbed from its position of stable equilibrium. The minimum time during which its gets aligned with the electric field.
Q.
How do capacitors increase DC voltage?
Q. a parallel plate capacitor (without dielectric) is charged by a battery and kept connected to the battery.a dielectric slab of dielectric constant K is inserted between the plates fully occupying the space between the plates.the energy density of electric field between the plates will
(1)increase K^2 times (2)decrease K^2 times (3)increase K times (4)decrease K times
Q. For the given charge distribution, net electric field at the centre of non-conducting ring is
(Assume that charge on first quadrant is neutral, second and third quadrant is positively charged, fourth quadrant is negatively charged )
(Assume that charge on first quadrant is neutral, second and third quadrant is positively charged, fourth quadrant is negatively charged )
- 185 N/C
- 285 N/C
- 384 N/C
- 484 N/C
Q. A thin uniformly charged ring of radius 1 m, charge +10 C and a semi-infinite charged wire of λ=+10 nC/m, oriented along the axis of ring with one of its ends coinciding with the centre of the ring, form a system. Find the force of interaction between the ring and wire.
- 600 N
- 700 N
- 800 N
- 900 N
Q. Capacitance of a parallel plate capacitor becomes 43 times its original value if a dielectric slab of thickness t=d2 is inserted between the plates [d is the separation between the plates]. The dielectric constant of the slab is
- 4
- 8
- 2
- 6
Q. The potential difference between points A and B is
Q. A parallel plate capacitor of capacitance C
has spacing d between two plates having area A. The region between the plates is filled with N dielectric layers, parallel to its plates, each with thickness δ=dN. The dielectric constant of the mth layer is Km=K(1+mN). For a very large N(>103), the capacitance C is α(K∈0Adln2). The value of α will be . [∈0 is the permittivity of free space]
has spacing d between two plates having area A. The region between the plates is filled with N dielectric layers, parallel to its plates, each with thickness δ=dN. The dielectric constant of the mth layer is Km=K(1+mN). For a very large N(>103), the capacitance C is α(K∈0Adln2). The value of α will be
Q. The charge on plate of capacitor varies as q=qosinwt and seperation between plates in very small as compared to area of the plate.The peak value of displacement current through capacitor
Q. A charged wire of length 3 m lies along x− axis in such a way that its linear charge density is given by λ=2x2 C/m. The total charge on the wire is
- 15 C
- 18 C
- 17 C
- 16 C
Q. Consider a parallel-plate capacitor of capacitance 10 μF with air filled in the gap between the plates. Now, one half of the space between the plates is filled with a dielectric of dielectric constant 4 as shown in the figure. The capacitance of the capacitor changes to
- 25 μF
- 20 μF
- 20 μF
- 40 μF
Q. A parallel plate capacitor with plate area A and plate separation d=2 m has a capacitance of 4 μF. The new capacitance of the system, if half of the space between them is filled with a dielectric material of dielectric constant K=3 (as shown in figure) will be:
Q. In the given circuit, potential difference between points A and B is (i.e VAB)
- +20 V
- -12 V
- +14 V
- +8 V
Q. An electric current is passed through a circuit containing two wires of the same material connected in parallel. If the lengths and radii of the wires are in the ratio of 4/3 and 2/3 respectively, then the ratio of the currents passing through the wires will be -
- 1/3
- 1/5
- 8/9
- 2
Q. Two large non-conducting plates having surface charge densities +σ and −σ respectively, are fixed d distance apart. A small test charge q of mass m is attached to two non-conducting springs, each of spring constant k as shown in the figure. The sum of lengths of both springs in undeformed state is d. The charge q is released from rest with both the spring undeformed. Then charge q will -
(Neglect gravity)
(Neglect gravity)
- Performs SHM with angular frequency √2km and amplitude σqkϵ0.
- Performs SHM with angular frequency √2km and amplitude σq2kϵ0.
- Does not perform SHM, but will execute periodic motion.
- Remains stationary.
Q. A dielectric slab of area A and thickness d is inserted between the plates of a capacitor of area 2A with constant speed v as shown in the figure. Distance between the plates is d.
The capacitor is connected to a battery of e.m.f. E; the current in the circuit varies with time as
The capacitor is connected to a battery of e.m.f. E; the current in the circuit varies with time as
- none of these
Q. A parallel-plate capacitor has a dielectric slab in it. The slab just fills the space inside the capacitor. The capacitor is charged by a battery and then the battery is disconnected. Now, the slab is pulled out slowly at t=0. If at time t, the capacitance of the capacitor is C and potential difference between the plates of the capacitor is V, then which of the following graphs is/are correct.
Q. An air capacitor of capacity C=10 μF is connected to a constant voltage battery of 12 V. Now the space between the plates is filled with a liquid of dielectric constant 5. The excess charge that flows now from battery to the capacitor is
- 120 μC
- 600 μC
- 240 μC
- 480 μC
Q. Consider the situation shown in figure.
The plates of the capacitor have plate area A and are clamped in the laboratory. The dielectirc slab is released from rest with a length a inside the capacitor. Neglecting any effect of friction or gravity, show that the slab will execute periodic motion and find its time period.
The plates of the capacitor have plate area A and are clamped in the laboratory. The dielectirc slab is released from rest with a length a inside the capacitor. Neglecting any effect of friction or gravity, show that the slab will execute periodic motion and find its time period.
- √mld(l−a)ε0AE2A(K−1)
- 2√mld(l−a)ε0AE2A(K−1)
- 4√mld(l−a)ε0AE2A(K−1)
- 8√mld(l−a)ε0AE2A(K−1)
Q. The charge on a capacitor plate in a circuit, as a function of time, is shown in the figure:
What is the value of current at t=4 s?
What is the value of current at t=4 s?
- 2 μA
- 1.5 μA
- 3 μA
- Zero
Q.
Write a function rule for “the output is half of the input.”
Q. Two long parallel wires P and Q placed at a separation of 6 cm carries electric currents, I1=5 A and I2=2 A respectively in the opposite directions as shown in the figure. Find the point on the line AB where the resultant magnetic field is zero.
- 4 cm away from B and 10 cm away from A
- 4 cm away from B and 2 cm away from A
- At the midpoint of AB
- None of these
Q. A parallel plate capacitor is made of two square plates of side ′a′, separated by a distance d(d<<a). The lower triangular portion is filled with a dielectric of dielectric constant K. The capacitance of this capacitor is :
- 12Kϵ0a2d
- Kϵ0a2dlnK
- Kϵ0a2d(K−1)lnK
- Kϵ0a22d(K+1)
Q. A parallel-plate capacitor with no dielectric has a capacitance of 0.5 μF. The space between the plates is filled with equal amounts of two dielectric materials of dielectric constants 2 and 3 as shown in the figure. Find the capacitance of the system.
- 1.2 μF
- 1.8 μF
- 1.25 μF
- None of these
Q. A parallel plate capacitor contains a mica sheet (thickness =10−3 m) and a sheet of fibre (thickness =0.5×10−3 m). The dielectric constant of mica is 8 and that of fibre is 2.5. Assuming that the fibre breaks down when subjected to an electric field of 6.4×106 V/m, find the maximum safe voltage that can be applied to the capacitor.
- 2.08 kV
- 2.08 V
- 9.6 kV
- 9.6 V
Q. A parallel plate air capacitor is made using two square plates each of side 0.2 m, spaced 1 cm apart. It is connected to a 50 V battery. What is the charge on each plate?
- 1.77×10−3C
- 1.77×10−3μC
- 3.54×10−3C
- 3.54×10−3μC
Q. a parallel plate capacitor is charged by a I=2*10^-7 . when discharge of the capacitor takes place through a resistance the rate of change of electric flux is??
Q. The capacitor plates are fixed on an inclined plane and connected to a battery of e.m.f. E. The capacitor plates have area A, length l and the distance between them is d. A dielectric slab of mass m and dielectric constant k is inserted into the capacitor and tied to a mass M by a massless string as shown in the figure. Find the value of M for which the slab will stay in equilibrium. There is no friction between slab and plates.
- m2+E2ε0A(k−1)2lgd
- m2−E2ε0A(k−1)2lgd
- m2−E2ε0A(k−1)lgd
- m2+E2ε0A(k−1)2lgd
Q.
How much energy can a capacitor store?