Perfectly Elastic Collision
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What are the differences between elastic and inelastic collisions?
Develop the theory of one-dimensional elastic collision.
- 1:3
- 1:4
- 1:2
- 1:√3
- Balls 1 and 2 comes to rest and ball 3 rolls out with speed v.
- Ball A comes to rest and balls 2 and 3 roll out with speed each.
- Balls 1, 2 and 3 roll out with speed each.
- Balls, 1, 2 and 3 come to rest.
- m(θ0+θ1θ0−θ1)
- m(θ0−θ1θ0+θ1)
- m2(θ0−θ1θ0+θ1)
- m2(θ0+θ1θ0−θ1)
What is impulsive force?
Two objects, each of mass , are moving in the same straight line but in opposite directions. The velocity of each object is before the collision during which they stick together. What will be the velocity of the combined object after collision?
- √32
- 23
- 13
- 16
- –0.3 m/s and 0.5 m/s
- 0.3 m/s and 0.5 m/s
- −0.5 m/s and 0.3 m/s
- 0.5 m/s and −0.3 m/s
A smooth sphere of mass 'M' moving with velocity 'u' directly collides elastically with another sphere of mass 'm' at rest. After collision their final velocities are 'V' and 'v' respectively. The value of 'v' is
- 4m√r
- 2mr
- 2m√r
- None of these
- v, 2v
- 4v, 0
- 2v, v
- v, v
- tan2θ
- cot θ
- cot2θ
- tan θ
[Take g=10 m/s2]
- x−coordinate of the striker when it stops (taking point O to be the origin and neglect the friction between wall and striker) is 12√2.
- y−coordinate of the stricker when it stops (taking point O to be the origin and neglect the friction between wall and striker) is 12.
- x−coordinate of the striker when it stops (taking point O to be the origin and neglect the friction between wall and striker) is 1√2.
- y−coordinate of the stricker when it stops (taking point O to be the origin and neglect the friction between wall and striker) is 12√2.
- hd=1−e2
- hd=1−e
- hd=11−e2
- hd=11−e
- Total momentum of the system is 3 kg m/s
- Momentum of 5 kg mass after collision is 4 kg m/s
- Kinetic energy of the centre of mass of system is 0.75 J
- Kinetic energy of the centre of mass of system is 1.75 J
(consider collision to be perfectly elastic)
- 15∘
- 30∘
- 60∘
- 45∘
A block of mass m 2.0 kg moving at 2.0 ms collides head on with another block of equal mass kept at rest.(a) Find the maximum possible loss in kinetic energy due to the collision.(b) If the actual loss in kinetic energy is half of this maximum, find the coefficient of restitution.
- −5 m/s and +2 m/s
- 3 m/s for both
- 5 m/s and 1 m/s
- None of these
In an elastic collision of two particles the following is conserved
Momentum of each particle
Speed of each particle
Kinetic energy of each particle
Total kinetic energy of both the particles
[Neglect friction between particle and the wedge and take M=2m, v0=10 m/s, tanα=2, g=10 m/s2.]
- 5 m/s
- 0 m/s
- 10 m/s
- 20 m/s
- 50√2 Ns
- 25√3 Ns
- 50√3 Ns
- 25 Ns
- 5 ms−1
- 10 ms−1
- 20 ms−1
- 40 ms−1
- 2m√2ghcosθ
- 2m√ghcosθ
- 2m√2ghsinθ
- 2m√2gh
- √GMR
- √3GMR
- √2GMR
- √5GMR
- mωm+M
- Mωm+M
- M+mMω
- ω2