Poisson's Effect
Trending Questions
- 0.4189 m/s
- 0.341 m/s
- 0.06912 m/s
- 0.887 mm/s
- −12
- 12
- −14
- 14
- 2.5%
- 4%
- 1%
- 2%
Two wires of diameter 0.25 cm, one made of steel and the other made of brass are loaded as shown in Fig. 9.13. The unloaded length of steel wire is 1.5 m and that of brass wire is 1.0 m. Compute the elongation of the steel and the brass wires.
What is the dimensional formula for compressibility?
- 5×10−5
- 1.25×10−5
- 10×10−5
- 2.5×10−5
- Zero
- Unity
- Infinity
- None
- √ΔLL
- ΔLL
- (ΔLL)3
- (ΔL2)2
- True
- False
- 2×109 NC−1
- 24×109 NC−1
- 48×109 NC−1
- 36×109 NC−1
A steel wire is stretched by a certain amount under a load. if the load and the radius both are increasing to 4 times find the stretch cause in wire
- 13
- 16
- 14
- 12
- 0.30
- 0.28
- 0.21
- 0.88
LENGTH DIAMETER
a) 100cm 1mm
b) 200cm 2mm
c) 300cm 3mm
d) 400cm 0.5mm
When a load of 20 kg is hung from a wire is cross-sectional area 1 sq mm, it's elongated length is 600.5 cm. If the load is withdrawn the wire shrinks by 0.5 cm in length. Calculate the youngs modulus of the wire?
A load of 10 kg is suspended by a metal wire 3 m long and hvaing a cross- sectional area 4mm2. Find (a) the stress (b) the strain and (c) the elongation. Young modulus of the metal is 2.0 ×1011Nm−2.
- 1Y=1B+1G
- 3Y=13B+1G
- 1Y=3B+1G
- 13Y=1B+3G
Two rods of identical dimension with youngs modulli Y1 and Y2 are joined end to end . The equivalent youngs modulus for the composite rod is (if the equivalent rod is also having same dimension as of the original rods)
Two wires one of Steel and other of aluminium each of 2 m long and diameter 20 mm are joined end to end and a composite wire of 4 m is formed. What is the tension in the wire producef on a total extension of 0.9 millimetres?
- 40×10−8cm2
- 50×10−8cm2
- 45×10−8cm2
- 22.5×10−8cm2
- 1%
- 2%
- 0.5%
- 0.25%
In Hookes law, the constant of proportionality signifies?
- Y > σ
- σ = +1
- Y = σ
- Y < σ
- 0.5
- 0.4
- 0.2
- 0.3
- 13
- 16
- 14
- 12