Position of a point
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Q. Acceleration of the particle in a rectilinear motion is given as a=4t+3 in (m/s2). The final position of the particle as a function of time t is
(Given, at t=0, u=3 m/s, x=2 m)
(Given, at t=0, u=3 m/s, x=2 m)
- 2t33+3t22+3t
- 2t33+3t22
- 2t33+3t22+3t+2
- 2t33+3t22−3t
Q. A body of mass 2 kg moves under a force of (2^i+3^j+5^k) N. It starts from rest and was at the origin initially. After 4 s, its new coordinates are (8, b, 20). The value of b is .
(Round off to the Nearest Integer)
(Round off to the Nearest Integer)
Q. If position of B with respect to P, is +2 m and position of C with respect to P is −4 m. Where B, P, C are the points along X−axis, then what will be the position of B with respect to C ?
- 3 m
- 6 m
- −5 m
- −2 m
Q. A body of mass 2 kg moves under a force of (2^i+3^j+5^k) N. It starts from rest and was at the origin initially. After 4 s, its new coordinates are (8, b, 20). The value of b is .
(Round off to the Nearest Integer)
(Round off to the Nearest Integer)
Q. In the given figure find
(i) position of A with respect to B
(ii) position of O with respect to B
(i) position of A with respect to B
(ii) position of O with respect to B
- (i) 5(ii) 3
- (i) −5(ii) 3
- (i) 5(ii) −3
- (i) −5(ii) −3
Q. Instantaneous velocity of an object varies with time as v=α−βt2. Find its position, x as a function of time, t. Also find the object`s maximum positive displacement, xmax from the origin.
- x=αt−βt33 and xmax=23α3/2β3/2
- x=αt−βt33 and xmax=2αβ1/2
- x=2αt−β and xmax=2αβ
- x=2α2t−βt3 and xmax=2α1/2β3/2
Q. Three balls initially at rest are released from the origin in the same direction and covers a distance of 5 m, 9 m and 15 m respectively. What will be the position of the ball farthest from the origin w.r.t the ball nearest to the origin?
- 4 m
- 6 m
- 9 m
- 10 m
Q. At t=0, a particle starts from (1, 0) and moves towards positive x−axis with speed of v=3t2+2t m/s. The final position of the particle as a function of time is
- 3t32−2t2+1 m
- 3t32+2t2+1 m
- t3+t2+1 m
- t3−t2+1 m
Q. At t=0, a particle starts from (−2, 0) and moves towards positive x−axis with speed of v=6t2+4t m/s. The final position of the particle and the distance travelled by the particle respectively, as a function of time are
- 2t3−2t2+2 m, 2t3−2t2 m
- 2t3+2t2−2 m, 2t3+2t2 m
- 2t3−2t2−2 m, 2t3+2t2 m
- 2t3−2t2+2 m, 2t3+2t2 m