Projectile to a Height:Angry Birds
Trending Questions
Q. An aeroplane moving horizontally with a speed of 720 km/h drops a food packet, while flying at a height of 396.9 m. The time taken by a food packet to reach the ground and its horizontal range is (Take g=9.8 m/sec2)
- 9 sec and 1800 m
- 3 sec and 2000 m
- 5 sec and 500 m
- 8 sec and 1500 m
Q. Equation of trajectory of an angry bird is Y = 10x - 59x2. What is the maximum height reached?
- 25 m
- 55 m
- 35 m
- 45 m
Q.
An airplane moving horizontally with a speed of 720 km/h drops a food pocket while flying at a height of 396.9 m. The time taken by a food pocket to reach the ground and its horizontal range is (Take g = 9.8 m/sec2)
3 sec and 2000 m
5 sec and 500 m
9 sec and 1800 m
8 sec and 1500 m
Q. A ball is thrown at different angles with the same speed u and from the same points and it has same range in both the cases. If y1 and y2 be the heights attained in the two cases, then y1+y2=
- u2g
- 2u2g
- u22g
- u24g
Q. An aeroplane moving horizontally with a speed of 720 km/h drops a food packet, while flying at a height of 396.9 m. The time taken by a food packet to reach the ground and its horizontal range is (Take g=9.8 m/sec2)
- 3 sec and 2000 m
- 5 sec and 500 m
- 8 sec and 1500 m
- 9 sec and 1800 m
Q. Equation of trajectory of an angry bird is Y = 10x - 59x2. What is the maximum height reached?
- 25 m
- 35 m
- 45 m
- 55 m
Q. The horizontal range and maximum height for a projectile is same. The angle of projectile is
- θ=tan−1(14)
- θ=tan−1(4)
- θ=tan−1(2)
- θ=45°
Q. An aeroplane moving horizontally with a speed of 720 km/h drops a food packet, while flying at a height of 396.9 m. The time taken by a food packet to reach the ground and its horizontal range is (Take g=9.8 m/sec2)
- 3 sec and 2000 m
- 5 sec and 500 m
- 8 sec and 1500 m
- 9 sec and 1800 m
Q. An aeroplane moving horizontally with a speed of 720 km/h drops a food packet, while flying at a height of 396.9 m. The time taken by a food packet to reach the ground and its horizontal range is (Take g=9.8 m/sec2)
- 3 sec and 2000 m
- 5 sec and 500 m
- 8 sec and 1500 m
- 9 sec and 1800 m
Q. Equation of trajectory of an angry bird is Y = 10x - 59x2. What is the maximum height reached?
- 25 m
- 35 m
- 45 m
- 55 m