Radial & Tangential Acceleration for Non Uniform Circular Motion
Trending Questions
Q. An object is tied to a string and rotated in a vertical circle of radius r. Constant speed (v) is maintained along the trajectory. If TmaxTmin=2, then v2rg=
Q.
A particle moves in a circle of radius 25 cm at two revolutions per second. The acceleration of the particle in m/s2 is
π2
8 π2
2 π2
4 π2
Q.
A car travels north with a uniform velocity. It goes over a piece of mud which sticks to the tyre. The particles of the mud, as it leaves the ground are thrown
Vertically upwards
Towards south
Vertically inwards
Towards north
Q.
A proton of mass 1.6×10−27 kg goes round in a circular orbit of radius 0.10 m under a centripetal force of 4×10−13N. then the frequency of revolution of the proton is about
0.08×108 cycles per sec
12×108 cycles per sec
8×108 cycles per sec
4×108 cycles per sec
Q. The bob of the pendulum shown in the figure describes an arc of a circle in a vertical plane. If the tension in the cord is 3 times of the weight of the bob for the position shown, the velocity of the bob at this position is


- 6.47 m/s
- 10 m/s
- 0 m/s
- 15 m/s
Q. A 1 kg stone at the end of a 1 m long string is whirled in a vertical circle at a constant speed of 4 m/s. The tension in the string is 6 N when the stone is (Take g=10 m/s2)
- At the top of the circle.
- At the bottom of the circle.
- Half way down
- None of above
Q. A small stone of mass 200 g is tied to one end of a string of length 80 cm. Holding the other end in the hand, the stone is whirled in a vertical circle. What is the minimum speed that needs to be imparted at the lowest point such that the stone is just able to complete the vertical circle?(Take g=10 m/s2)
- 4 m/s
- 5.13 m/s
- 6.32 m/s
- 7 m/s
Q. A stone of mass 1 kg tied to a light string of length 103 m is whirled in a vertical circle. If the ratio of the maximum tension to minimum tension is 4 and g=10 m/s2, then the speed of the stone at the highest point of the circle is
- 20 m/s
- 10 m/s
- 5 m/s
- 0 m/s
Q. The bob of a pendulum at rest is given a sharp hit to impart a horizontal velocity u=√10gl, where l is the length of the pendulum. Then, the tension in the string when it is horizontal is xmg where x=


Q. The bob of a pendulum at rest is given a sharp hit to impart a horizontal velocity u=√10gl, where l is the length of the pendulum. Find the velocity of the bob when the string is horizontal.


- √2gl
- √4gl
- √6gl
- √8gl