Range
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- 125√3 m
- 200√3 m
- 500 m
- 250√3 m
- R
- 1R
- 1R2
- R2
- 75∘
- 60∘
- 90∘
- 180∘
A projectile is projected with initial velocity (6^i+8^j)m/sec. If g=10 ms−2, then horizontal range is
4.8 metre
9.6 metre
19.2 metre
14.0 metre
- √2gh
- √3gh
- √gh
- √6gh
The maximum horizontal range of a projectile is 400 m. The maximum value of height attained by it will be
200 m
100 m
400 m
800 m
- 22 m
- 6 m
- 15 m
- 11 m
A projectile fired with initial velocity u at some angle θ has a range R. If the initial velocity be doubled at the same angle of projection, then the range will be
2R
R
R2
4R
A bullet fired at an angle of degrees with the horizontal hits the ground away. By adjusting its angle of projection, can one hope to hit a target away? Assume the muzzle speed to be fixed, and neglect air resistance.
An object is thrown along a direction inclined at an angle of 45∘ with the horizontal direction. The horizontal range of the particle is equal to
Vertical height
Twice the vertical height
Thrice the vertical height
Four times the vertical height
When a particle is projected at an angle to the horizontal, it has range R and time of flight t1. If the same projectile is projected with the same speed at another angle to have the same range and time of flight t2 then,
t1+t2=2Rg
t1, t2=2Rg
t1−t2=2Rg
t1t2=2Rg
- 1:3
- 1:1
- √3:1
- 1:√3
Figure shows four paths for a kicked football. Ignoring the effects of air on the flight, rank the paths accoding to initial horizontal velocity component, highest first
1, 2, 3, 4
2, 3, 4, 1
3, 4, 1, 2
4, 3, 2, 1
Four bodies P, Q, R and S are projected with equal velocities having angles of projection 15∘, 30∘, 45∘ and 60∘ with the horizontal respectively. The body having shortest range is
P
Q
S
R
If the range of a gun which fires a shell with muzzle speed V is R , then the angle of elevation of the gun is
cos−1(V2Rg)
12(V2Rg)
12sin−1(gRV2)
cos−1(gRV2)
Two particles A & B are projected with same speed so that the ratio of their maximum height reached is 3:1. If the speed of A is doubled without altering other parameters, the ratio of their horizontal ranges is
1:1
2:1
4:1
3:2
A projectile is thrown into space so as to have maximum horizontal range R. Taking the point of projection as origin, the co-ordinates of the point where the speed of the particle is minimum are
- 15∘
- 60∘
- 70∘
- 30∘
- 2:1
- √6:1
- √3:1
- 1:2
1.5 km
3.0 km
6 km
0.75 km
- 4v25g
- 4g5v2
- v2g
- 4v2√5g
An object is projected at an angle of 45∘ with the horizontal. The horizontal range and the maximum height reached will be in the ratio.
2 : 1
1 : 4
1 : 2
4 : 1
A projectile thrown with a speed vat an angle θhas a range Ron the surface of earth. For same vand θ, its range on the surface of moon will be
6R
R36
36R
R6
A boy playing on the roof of a 10m high building throws a ball with a speed of 10 m/s at an angle of 30∘ with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground (g=10 m/s2, sin 30∘=12, cos 30∘=√32)
8.66 m
2.60 m
5.20 m
4.33 m
- Have dispersion without average deviation
- Have deviation without dispersion
- Have both dispersion and average deviation
- Have neither dispersion nor average deviation
- 5kmh−1
- 1kmh−1
- 3kmh−1
- 4kmh−1
A particle covers 50 m distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed
100 m
150 m
200 m
250 m
- 4√2 m/s
- 5 m/s
- 5√2 m/s
- 10√2 m/s
- v0√2Hg
- v0mM+m√2Hg
- v0Mm√2Hg
- v0mM√2Hg