Refraction at a Spherical Surface
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- √3
- √2
- 32
- 12
- Image is virtual if the object distance is less than 90 cm
- Image is real if the object distance is greater than 90 cm
- Image is always real
- Image is always virtual
- 1.2
- 1.5
- 1.8
- 2
[measured from the surface AB]
- 36 cm
- 18 cm
- 24 cm
- 16 cm
Light falls from glass (μ=1.50) to air. Find the angle of incidence for which the angle of deviation is 90∘.
- 10 cm
- 15 cm
- 50 cm
- None
- Virtual and at a distance of 16 cm from the mirror
- Virtual and at a distance of 20 cm from the mirror
- Real and at a distance of 16 cm from the mirror
- Real and at a distance of 20 cm from the mirror
- |f1|=3R
- |f1|=2.8R
- |f2|=2R
- |f2|=1.4R
A light ray suffers minimum deviation while passing through a prism of refractive index and refracting angle . Calculate the angle of deviation and angle of incidence.
- 2R
- R
- 3R2
- R2
- 10 cm from point D
- 22.5 cm from point D
- 30 cm from point D
- 20 cm from point D
(b) Two polaroids P1 and P2 are placed with their pass axes perpendicular to each other. Unpolarised light of intensity I0 is incident on P1. A third polaroid P3 is kept in between P1and P2 such that its pass axis makes an angle of 30∘ with that of P1. Determine the intensity of light transmitted through P1, P2 and P3.
- 3.2 cm
- 2.8 cm
- 1.2 cm
- 1.6 cm
- 10 cm
- 15 cm
- 50 cm
- None of these
- yellow ray travels without deviation
- blue ray is deviated towards the vertex
- red ray is deviated towards the base
- there is no dispersion
- D2
- D3
- 2D3
- 34D
- 12 cm
- 30 cm
- 50 cm
- 60 cm
Light is incident from glass (μ=1.5) to air. Sketch the variation of the angle of deviation δ with the angle of incident i for 0<i<90∘.
A ray of light is incident on the surface of a sphere of refractive index μ=√52 . After refraction, it is total internally reflected and refracted out of the sphere again such that the total deviation is minimum. The angle of incidence of the ray is
- 530
- 300
- 600
- 450
One end of a cylindrical glass rod shown in figure ends in a hemispherical surface of radius R = 20 mm.
-Let the same rod be immersed in water of index 1.33, the other quantities having the same values as before. Find the image distance.
120 mm
-120 mm
180 mm
-180 mm
A plane glass slab is kept over various coloured letters. The letter which appears least raised is
Violet
Blue
Green
Red
Locate the image of the point object O in the situation shown in the figure with respect to the pole P of the spherical surface. The point C denotes the centre of curvature of the refracting surface.
30 cm, Left
30 cm, Right
20 cm, Right
20 cm, Left
- 0
- tsin(i−r)cosr
- tsinicosr
- tsin(i−r)cosr
A ray of light undergoes refraction and loses times its velocity. If i is the angle of incidence and is very small, the angle of deviation for the ray of light is______
- x=1807 cm
- x=40 cm
- x=403 cm
- x=−403 cm
(Assume that spherical interface always seperates air and medium of refractive index 1.5)
An air bubble in sphere having 4 cm diameter appears 1 cm from surface nearest to eye when looked along diameter. If amg = 1.5, the distance of bubble from refracting surface is
[CPMT 2002]
1.2 cm
3.2 cm
2.8 cm
1.6 cm
- image is always real
- image is real if the object distance is greater than 90 cm
- image is always virtual
- image is virtual if the object distance is less than 90 cm