Resultant Wave Equation
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- a wave travelling in positive x-direction with a velocity 1.5 m/s
- a wave travelling in the negative x-direction having a wavelength 0.4 m
- a wave travelling in negative x-direction with a velocity1.5 m/s
- a wave travelling in positive x-direction of wavelength 0.1 m
- travelling with a velocity of 30 m/s in the negative x-direction
- of wavelength π m
- of frequency (30/π) Hz
- of amplitude 10−4 m travelling along the negative x-direction
- there is a gain of energy
- there is a loss of energy
- the energy is redistributed and the distribution changes with time
- the energy is redistributed and the distribution remains constant in time
y1=10sin[π(8x−1400t)]
and y2=10sin[π(8x−1400t−0.5)] Where x, y1, and y2 are in metres and t is in seconds . which of the following options is/are correct ?
- Amplitude of the resultant wave is 10√2 m
- Frequency of the resultant wave is 700 Hz
- Time period of the resultant wave is 0.1 s
- None of these
- m=20 kg
- M=5 kg
- mM=12
- mM=2
- p=p0 sin (kx−ωt)
- p=p0 sin kx cosωt
- p=p0 cos kx sin ωt
- p=∑pon sin (knx−ωnt)
- 4000 N
- 400 N
- 45 N
- 250 N
- 0.0173sinπt−0.05cosπt
- 0.0173sinπt−0.017cosπt
- 0.05sinπt−0.0173cosπt
- 0.05sinπt−0.5cosπt
y1=4 sin ωt , and
y2=3 sin(ωt+π3)
(where y1, y2 are in cm and t is in sec),
interfere at a point, the resultant amplitude of that point will be about,
- 7 cm
- 6 cm
- 5 cm
- 3.5 cm
- √a21+a22
- a21+a22
- a1+a2
- a1−a2
- 0.5
- 1
- 2
- 4
x=[3sin(4t)+4sin(4t)] cm . The amplitude and maximum speed of the particle during oscillation will be
- 4 cm, 2 cm s−1
- 2 cm, 4 cm s−1
- 10 cm, 5 cm s−1
- 5 cm, 20 cm s−1
- 100 cm
- 5 m
- 200 cm
- 1000 cm
- A standing wave having nodes at
x=(n+12)λ2, n=0, 1, 2 - A standing wave having nodes at nλ2;n=0, 1, 2
- A wave travelling along +x direction
- A wave travelling along −x direction
A block of mass m=10 kg is hanging. If mass of string is 0.01 kg and length of string is 1 m. Find the number of loop formed if a standing wave is set on the string. Frequency of the wave is given as 50 Hz.
- 1
- 2
- 4
- 3
y=Asin(ωt−kx)
The maximum velocity of a particle of the wave is
- Aω
- ω/k
- dω/dk
- x/l
- ω1=ω3>ω2
- ω1>ω2>ω3
- ω2>ω1=ω3
- ω1=ω2=ω3
Two harmonic waves are represented in SI units by, y1 (x, t) = 0.2 sin (x − 3.0t) and y2 (x, t) = 0.2 sin (x−3.0t + ϕ). What is the expression for the sum y = y1 + y2 for ϕ =π2.
y = 8 sin (x - 3.0t)
y = 0.28 sin (x - 3.0t+π4)
y = 0.2 sin (x - 3.0t+π4)
y = 0.28 cos (x - 3.0t+π4)
- 300 m/s
- 200 m/s
- 600 m/s
- 1200 m/s
Where x=0 at one end of the rope, x is in meters and t is in seconds. The length of the rope is
- 220√2 V
- 220 V
- 314 V
- 220/√2 V
Two harmonic waves are represented in SI units by, y1 (x, t) = 0.2 sin (x − 3.0t) and y2 (x, t) = 0.2 sin (x−3.0t + ϕ). What is the expression for the sum y = y1 + y2 for ϕ =π2.
y = 8 sin (x - 3.0t)
y = 0.28 sin (x - 3.0t+π4)
y = 0.2 sin (x - 3.0t+π4)
y = 0.28 cos (x - 3.0t+π4)
y(x, T)=2sin(2π3x)cos(100πt) Where x and y are in cm and t is in s. Which of the following statement is correct?
- All the points on the string between two consecutive nodes vibrate with same frequency, phase and amplitude.
- All the points on the string between two consecutive nodes vibrate with same frequency, phase but different amplitude.
- All the points on the string between two consecutive nodes vibrate with different frequency and phase but same amplitude.
- All the points on the string between two consecutive nodes vibrate with different frequency, phase and amplitude.
Two harmonic waves are represented in SI units by, y1 (x, t) = 0.2 sin (x − 3.0t) and y2 (x, t) = 0.2 sin (x−3.0t + ϕ). What is the expression for the sum y = y1 + y2 for ϕ =π2.
y = 8 sin (x - 3.0t)
none of these