Rotational Work and Energy
Trending Questions
- angular momentum of projectile about origin remains conserved
- angular momentum of the projectile about origin when it just starts its motion is zero
- angular momentum of projectile about origin when it reaches the highest point is m√gh3
- angular momentum of projectile about origin when it reaches the highest point is m√2gh3.
- √gL
- 12√gL
- 32√gL
- 2√gL
- k2k2+R2
- R2k2+R2
- k2+R2R2
- k2R2
- −MB
- +MB
- 0
- +2MB
What is the radius of gyration? On what factors its depends?
- 7 m/s
- 10 m/s
- 15 m/s
- 20 m/s
45 _————— o 10 m P
A disc of radius R is cut out from a larger disc of radius 2R in such a way that the edge of the hole touches the edge of the disc.Locate the centre of mass of the residual disc.
- 8 m/s
- 0.5 m/s
- 2 m/s
- 1 m/s
- 1R√4gh3
- 1R√2gh3
- R√2gh3
- R√4gh3
- v22g
- v23g
- 3v24g
- v24g
- mv2
- 43mv2
- 45mv2
- None of these
A body having a moment of inertia about its axis of rotation equal to 3 kg-m2 is rotating with the angular velocity of 3 rad s−1. The kinetic energy of this rotating body is the same as that of a body of mass 27 kg moving with velocity v. The value of v is-
1 m/s
1.5 m/s
2.5 m/s
2 m/s
No work is done when
a nail is plugged into a wooden board
a box is pushed along a horizontal floor
there is no component of force parallel to the direction of motion
there is no component of force normal to the direction of motion.
- 1:4
- 4:1
- 8:1
- 1:8
- [2(m1−m2)gh(m1+m2)R2+I]1/2
- [2(m1+m2)gh(m1+m2)R2+I]1/2
- [(m1−m2)(m1+m2)R2+I]1/2gh
- [(m1+m2)(m1+m2)R2+I]1/2gh
- The force is always perpendicular to acceleration of object.
- The object is at rest relative to ground but the point of application of force moves on the object.
- The force is always perpendicular to velocity of object.
- The point of application of force is fixed relative to ground but the object moves.
The angular speed of cylinder, when it has rotated through 90∘ in anticlockwise direction.
(Take g=10 m/s2)
- √5 rad/s
- 2√3 rad/s
- √10 rad/s
- 4√2 rad/s
- 1467 J
- 1452 J
- 1567 J
- 1632 J
- 250 J
- 500 J
- 10 J
- 100 J
- 12
- 13
- 14
- 15
- √cosα
- sinα
- √sinα
- cosα
- 2 : 1
- 3 : 1
- 4 : 1
- 5 : 1
No work is done by a force on an object if
a) force is always perpendicular to its velocity
b) the object is stationary but the point of application of force moves on the object
c) the object moves in such a way that the point of application Of the force also moves
d) the force is always perpendicular to its acceleration.
- Tension in any of the rod after collision is mv2o36l
- Tension in any of the rod after collision is mv2o28l
- Loss of energy due to collision is 7mv2o12
- Loss of energy due to collision is 7mv2o24
- 0 J
- 4 J
- 2 J
- 2π J
- mechanical energy as well as momentum is conserved in all direction.
- mechanical energy is conserved but momentum is not conserved in all directions.
- mechanical energy as well as momentum is not conserved.
- mechanical energy is not conserved but momentum is conserved in all directions.
Work done by normal contact force on an object can be non-zero. Explain this statement.