Solenoid
Trending Questions
The earths magnetic field at the equator is approximately . What is the earths dipole moment?.
- q is negative and |Q|<|q|
- Q is positive and |Q|>|q|
- Q is negative and |Q|>|q|
- q is positive and |Q|<|q|
- μ0I2πd(√2−1)
- μ0I4πd(√2−1)
- μ0I2πd(1+1√2)
- μ0I2πd(1−1√2)
- μ0i2√3πa⊗
- μ0i2√3πa⊙
- 2√3μ0iπa⊙
- zero
The dimensional formula for the magnetic moment of a magnet is.
- (√2π+2)μ0I8√2πR
- 3(√2π+1)μ0I8√2πR
- (3√2π+2)μ0I8√2πR
- (√2π+1)μ0I4√2πR
- 12.6×10−3Weberm2, 6.3×10−3Weberm2
- 12.6×10−3Weberm2, 25.1×10−3Weberm2
- 25.1×10−3Weberm2, 12.6×10−3Weberm2
- 25.1×10−5Weberm2, 6.3×10−5Weberm2
The magnetic intensity H at the centre of a long solenoid carrying a current of 2.0 A, is found to be 1500 A m−1. Find the number of turns per centimetre of the solenoid.
B) Predict the direction of induced current in the situation described by the following figure
C) Predict the direction of induced current in the situation described by the following figure
D) Predict the direction of induced current in the situation described by the following figure
E) Predict the direction of induced current in the situation described by the following figure
F) Predict the direction of induced current in the situation described by the following figure
- 2:√5
- 64:125
- 16:25
- 4:5
- R√3
- R√2
- 2R√3
- R√3
A copper wire having resistance 0.01 ohm in each metre is used to wind a 400-turn solenoid of radius 1.0 cm and length 20 cm. Find the emf of a battery which when connected across the solenoid will cause a magnetic field of 11.0×10−2 T near the centre of the solenoid.
- 20 kV
- 23 kV
- 26 kV
- 29 kV
- Directly proportional to current
- Directly proportional to its length
- Inversely proportional to total number of turns
- Inversely proportional to current
- 3.66 H
- 9 H
- 0.66 H
- 1 H
The magnetic field B inside a long solenoid, carrying a current of 5.00 A, is 3.14×10−2 T. Find the number of turns per unit length of the solenoid.
- i1≠i2 and n1=n2
- i1=i2 and n1≠n2
- i1≠i2 and n1=n2
- i1n1=i2n2
- →B=2μ0I5πa ^i+μ0I5πa ^j
- →B=μ0I2πa ^i−μ0I5πa ^j
- →B=2μ0I5πa ^j
- →B=μ0I5πa ^i−μ0I5πa ^j
- μ04πIa
- μ0I4πa2√3
- μ0I2πa2√3
- None of these
- πIB(R12+R22)
πIB(R12+R22)2- πIB(R22−R12)
- πIB(R22−R12)2
A tightly-wound, long solenoid is kept with its axis parallel to a large metal sheet carrying a surface current. The surface current through a width dl of the sheet is Kdl and the number of turns per unit length of the solenoid is n. The magnetic field near the centre of the solenoid is found to be zero. (a) Find the current in the solenoid. (b) If the solenoid is rotated to make its axis perpendicular to the metal sheet, what would be the magnitude of the magnetic field near its centre ?
- 4μ0Iπa
- 4μ0I√3πa
- μ0Iπa
- μ0I3πa
- μ02πid
- μ0 i4π d(1−√3)
- μ04πid(2−√3)
- μ0πid