Standing Wave Visualization
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- 2 cm
- 16 cm
- 4 cm
- 8 cm
What is out of phase in physics?
A wave is described by the equation y=(1.0 mm)sin π(x2.0 cm−t0.01 s)
(a) Find the time period and the wavelength ? (b) Write the equation for the velocity of the particles. Find the speed of the particle at x = 1.0 cm at time t = 0.01 s. (c) What are the speeds of the particles at x = 3.0 cm, 5.0 cm and 7.0 cm at t = 0.01 s ? (d) What are the speeds of the particles at x = 1.0 cm at t = 0.011, 0.012, and 0.013 s?
A wave represented by the equation is superposed with another wave to form a stationary wave such that point is a node. The equation for the other wave is
Column-I | Column-II | ||
(A) | A tight string is | (P) | At the middle, antinode is formed fixed at both ends in odd harmonic and sustaining standing wave |
(B) | A tight string is | (Q) | At the middle, node fixed at one end is formed in even and free at ond harmonic and free at the other end |
(C) | Standing wave is | (R) | At the middle, neither formed in an open node nor antinode is organ pipe. End correction formed is not negligible |
(D) | Standing wave is | (S) | Phase difference formed in a closed between SHMs of organ pipe. End any two particles correction is not will be either or negligible zero. |
- B → P, R
- D → R, S
- C → P, Q
- A → Q, R
- Amplitude of motion is 4a
- Time period of oscillations is 6τ
- Amplitude of motion is 3a
- Time period of oscillations is 8τ
- y=AsinπxLsinωt, has 2 nodes.
- y=AcosπxLsinωt, has 2 antinodes.
- y=Asin2πxLsinωt, has 2 antinodes.
- y=Acos2πxLsinωt, has 2 nodes.
- 5 m
- 32 m
- 8 m
- 10 m
- 0.5 and 0.8 from left
- 0.4 and 0.6 from left
- 0.7 and 0.5 from left
- 0.6 and 0.9 from left
- The fundamental frequency is 100 Hz
- The number of nodes is 5
- The length of the string is 0.25 m
- The maximum displacement of the midpoint of the string, from its equilibrium position is 0.1 m
in every period of oscillation.
- twice
- only once
- thrice
- The length of the string is 0.25 m
- The maximum displacement of the midpoint of the string, from its equilibrium position is 0.01 m
- The fundamental frequency is 100 Hz
- The number of nodes is 5
y=cos2πtsin2πx then minimum length of string is
- 1m
- 12m
- 5m
- 2πm
difference between wave and particle?
- 2ms−1
- 1.25ms−1
- 1.5ms−1
- 1ms−1
- Amplitude of all the particles is equal.
- All the particles are vibrating in the same phase.
- Particles of the medium executes SHM.
- Wave velocity depends upon the nature of the medium.
- 7.5
- 15
- 30
- 22.5
y=(6.0cm)cosπ2[(2.00m−1)x+(8.00s−1)t]
and a generator at the other end creates the wave
y=(6.0cm)cosπ2[(2.00m−1)x−(8.00s−1)t]
For x≥0, what is the location of the node having the smallest value of x?
y=(6.0cm)cosπ2[(2.00m−1)x+(8.00s−1)t]
and a generator at the other end creates the wave
y=(6.0cm)cosπ2[(2.00m−1)x−(8.00s−1)t]
For x≥0, what is the location of the antinode having the third smallest value of x?
y=(6.0cm)cosπ2[(2.00m−1)x+(8.00s−1)t]
and a generator at the other end creates the wave
y=(6.0cm)cosπ2[(2.00m−1)x−(8.00s−1)t]
For x≥0, what is the location of the node having the second smallest value of x?
What name has been given to the wave of short duration?
Pulse
Periodic wave
Elastic wave
None of these
y1=0.050cos(πx−4πt)
and y2=0.050cos(πx+4πt)
where x, y1, and y2 are in meters and t is in seconds. (a) What is the smallest positive value of x that corresponds to a node? Beginning at t=0?
- displacement
- velocity
- wavelength
- time
- 20units
- 10units
- 100units
- 200units
Two points on string are being observed as a travelling wave passes them. Then point are at x1=0 a x2=1m, the transverse motions of two points are found to be as follows.
y1=Asin(3πt) and y2=Asin(3πt+π8)t is in seconds and y in metre. Mark correct options.
- Frequency of wave is 3Hz
- Frequency of wave is 1.5Hz
- Wavelength may be 16m
- Wavelength may be 1617m
- True
- False